Discussion :: Chemical Engineering Basics - Section 6 (Q.No.2)
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Ashok Kumar said: (Aug 22, 2016) | |
= (170 - 70) / (150 - 50), ln (100 / 100) is equal to infinity. |
Romil Kikani said: (Feb 18, 2017) | |
I think it is logarithmic mean, not an arithmetic mean. |
Sk Jha said: (Apr 6, 2017) | |
@Ashok I don't think so. AMTD = (170+150)/2 - (70+50)/2, = 320/2 - 120/2, = 160 - 60 = 100 Ans. |
Tejprakash said: (Dec 26, 2017) | |
Yes, I agree with you @Ashok. |
Raj Musale said: (Sep 9, 2019) | |
The answer is 100° C. |
Nilesh Singh said: (Nov 20, 2020) | |
T1 = 170 - 150 = 20, T2 = 50 - 70 = -20. AM=20+(-20)/2= infinity. |
Neeraj Kumar said: (Sep 28, 2021) | |
LMTD= ΔT1/ln(ΔT1/ΔT2) ΔT1=170-70 = 100. ΔT2=150-50 = 50. Then LMTD = 100/Ln(100/100), = 100/0. = ~ infinite. Options D is the right answer. |
Nitesh Ghidode said: (Oct 5, 2021) | |
It's a log mean temperature difference. |
Nitesh Ghidode said: (Dec 1, 2021) | |
Answer should be 100 for AMTD and Infinite for LMTD. |
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