C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 5)
5.
What will be the output of the program If the integer is 4bytes long?
#include<stdio.h>
int main()
{
int ***r, **q, *p, i=8;
p = &i;
q = &p;
r = &q;
printf("%d, %d, %d\n", *p, **q, ***r);
return 0;
}
Discussion:
35 comments Page 1 of 4.
Reddy Royal said:
5 years ago
Thanks @Kiran Kumar.
Niya said:
5 years ago
Right, thanks @Shubham Patil.
Shubham Patil said:
5 years ago
Here i = 8.
1) As p=&i is representing the value of i is 8.
2) q=&p => stores the address of p.
*q is the address stored in q ie address of p.
**q = value at address at p i.e. 8.
3) r=&q
Therefore *r= address of q.
**r= *(*q).
***r= *(*(*q)).
That i the value stored in p = 8.
Hence the answer is 8 8 8.
1) As p=&i is representing the value of i is 8.
2) q=&p => stores the address of p.
*q is the address stored in q ie address of p.
**q = value at address at p i.e. 8.
3) r=&q
Therefore *r= address of q.
**r= *(*q).
***r= *(*(*q)).
That i the value stored in p = 8.
Hence the answer is 8 8 8.
(5)
Divya said:
7 years ago
Thanks @Sunil Pradhan.
(2)
Prajakta said:
7 years ago
Thank you very much @Sunil pradhan.
(1)
Preethi said:
7 years ago
Thank you @Keerthi. Nice explanation.
Sujata said:
8 years ago
@Sunil Pradhan.
Well explained, thanks!
Well explained, thanks!
(1)
Shivani agrawal said:
8 years ago
i=8;
p=&i implies *p=8;
q=&p implies *q=p means **q=8;
r=&q implies *r=q means ***r=8;
So, *p=**q=***r=i=8;.
p=&i implies *p=8;
q=&p implies *q=p means **q=8;
r=&q implies *r=q means ***r=8;
So, *p=**q=***r=i=8;.
(1)
Sujit said:
8 years ago
@Jyothi.
The Explanation is perfect. Thanks.
The Explanation is perfect. Thanks.
SONY said:
8 years ago
Thank you all for providing very good explanations.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers