C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 5)
5.
What will be the output of the program If the integer is 4bytes long?
#include<stdio.h>
int main()
{
int ***r, **q, *p, i=8;
p = &i;
q = &p;
r = &q;
printf("%d, %d, %d\n", *p, **q, ***r);
return 0;
}
Discussion:
35 comments Page 2 of 4.
Akshansh Yadav said:
9 years ago
Great explanations. Thank you all.
Keerthana said:
9 years ago
Thanks for your answers.
Shefali said:
9 years ago
@Jyothi is explained well.
Abi said:
9 years ago
@All. Thank you for the explanation.
Sujan said:
9 years ago
p=&i;
therefore, *p=i; -> *p=8;
q=&p;
therefor, *q=p; **q=*p; -> **q=8;
r=&q;
therefor *r=q; **r=*q; ***r=**q=8!
therefore, *p=i; -> *p=8;
q=&p;
therefor, *q=p; **q=*p; -> **q=8;
r=&q;
therefor *r=q; **r=*q; ***r=**q=8!
Harendra gotla said:
9 years ago
Thank you @Sumallika, the way you solve the problem is clever and easy to understand.
Manjiri shastri said:
10 years ago
Can you please tell me how it work? I mean how pointer storing the address?
Sumallika said:
1 decade ago
p=&i
*p=*(&i)=i
so *p=8;
q=&p,
*q=*(&p)=p,
**q=*p,
**q=8;
r=&q,
*r=*(&q)=q
**r=*q,
***r=**q,
***r=8
*p=*(&i)=i
so *p=8;
q=&p,
*q=*(&p)=p,
**q=*p,
**q=8;
r=&q,
*r=*(&q)=q
**r=*q,
***r=**q,
***r=8
Ramya said:
1 decade ago
Here r contains ***r so it point the i pointer variable.
And q contain the ** pointer variable. And p contain the * pointer variable so it point the i pointer address value.
And q contain the ** pointer variable. And p contain the * pointer variable so it point the i pointer address value.
Shashank sinha said:
1 decade ago
Thanx Jyoti
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