C Programming - Expressions - Discussion
Discussion Forum : Expressions - Find Output of Program (Q.No. 12)
12.
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=2;
printf("%d, %d\n", ++i, ++i);
return 0;
}
Answer: Option
Explanation:
The order of evaluation of arguments passed to a function call is unspecified.
Anyhow, we consider ++i, ++i are Right-to-Left associativity. The output of the program is 4, 3.
In TurboC, the output will be 4, 3.
In GCC, the output will be 4, 4.
Discussion:
43 comments Page 1 of 5.
Usha said:
3 years ago
But its prints the latest value 4, 4 only. Am I right?
Piyush Watmode said:
4 years ago
Actully, the output in gcc compiler is 4, 4.
(1)
Ganesh said:
7 years ago
I am not getting it. Please explain me.
(1)
Giriprasad said:
8 years ago
It is prinetd in left to right. If it is printed in right to left then the output is 3, 4.
(2)
Salim shaikh said:
8 years ago
Main
{
int I=23;
int J
J=I++;
Printf(",,...d",J);
}
Please tell me in this case why error occurs?
{
int I=23;
int J
J=I++;
Printf(",,...d",J);
}
Please tell me in this case why error occurs?
Sathya said:
8 years ago
int j=5,s=5,i=0,m=5,n=5,q=0,h=5;
i=m++ + ++n-j-- - --s;
q=h++ + ++h - h-- - --h;
System.out.println("q:"+q);
System.out.println("i:"+i);
System.out.println("j:"+j);
System.out.println("s:"+s);
System.out.println("j:"+m);
System.out.println("s:"+n);
can you explain this one?
i=m++ + ++n-j-- - --s;
q=h++ + ++h - h-- - --h;
System.out.println("q:"+q);
System.out.println("i:"+i);
System.out.println("j:"+j);
System.out.println("s:"+s);
System.out.println("j:"+m);
System.out.println("s:"+n);
can you explain this one?
Ramkumar said:
8 years ago
in turbo C o/p is 4,3.
in c++ o/p is 3,4.
in GCC o/p is 4,4.
Thus the answer will be option D : output will vary from compiler to compiler.
in c++ o/p is 3,4.
in GCC o/p is 4,4.
Thus the answer will be option D : output will vary from compiler to compiler.
Kartheek said:
9 years ago
In Linux 4,4 because the priority is from right to left. If pre-increment is there from right to left then the variable is updated.
Ankit kumar said:
9 years ago
It is mentioned here that in GCC compiler output will be 4 4. How? Explain please.
Pavani said:
1 decade ago
Sorry displayed in right to left order.
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