C Programming - Control Instructions - Discussion

Ans 0 is True.

Because x= -1
Negative value stored in 2'nd compliment.
(-1 ) 2nd compliment value is definatly x>10.


And for loop condition is x<=10.
Condition False and out of the loop.

So, the Ans is 0.

Here, printf("IndiaBIX");: this statement is intended to print "IndiaBIX" but it's placed after the break statement. So it didn't print anything.

Correct me, If I'm wrong.

Continue will throw the controller to the beginning of the loop while break will terminate the loop.

Since -1<=10 for loop get initialised.

Also, -1 <5 if the condition is true.

The printf("IndiaBIX"); statement gets skipped because of the continue statement that immediately follows it.

Continue statement directly goes to the next iteration skipping the code below it so printf does get executed

@All.

According to my knowledge.

#include<stdio.h>
int main()
{
int x;
for(x=-1; x<=10; x++)

/* (i) for loop is initialized with x=-1 and condition x<=10............... */
{
if(x < 5)
continue;

/* (i) First time ->
if (-1<5) , condition true -> continue statement transfer the control to for loop...
(ii) Last time ->
if (5<5) , condition false -> the else part will execute....
*/

else
break;

/* (i) -> the break statement make sure the for loop is terminated.........
(ii) -> it will not print IndiaBix because for loop has been terminated.............. */

printf("IndiaBIX");
}
return 0;
}

Hello ,please give me the suggestion for this.

#include<stdio.h>
int a,b,z,c;
float x=0.00,y;
float value=200;
void main()
{
x=value/200;
a=x;
y=x-a;
b=23*y;


for(z=0;z<23*a;z+=23)
{
printf("\n Z:%d ",z);
}
if(z<=z*a)
{
c=z;
z=c+b;

In a above code, I want a 23 value print on printf line. Now I am getting the 0 value. How to predict it? please tell me.

When x=-1 to x=4 in this case, continue statement executed by increasing value of x only not go to print statement

When x=5 in this case break statement executed and loop will terminated

So zero times print statement executed.

#include<stdio.h>
int main()
{
int x;
for(x=-1; x<=18; x++)
{
if(x<5)
printf("\nIndiaBIX");
else
break;
printf("\nIndiaBIX");

}
return 0;
}
Output is 12.

Please explain.

The condition x<5 is true until x=5, so the true block executed. The code after the continue statement(including printf("IndiaBIX");) will not executed and go to increment step(x++). Again the loop is continued.

When x=5, then else block executed, it has break statement, So loop is terminated.

Here the control never go to printf("IndiaBIX"); statement.

After 6 loops it will exit.