C Programming - Control Instructions - Discussion

Discussion Forum : Control Instructions - General Questions (Q.No. 1)
1.
How many times "IndiaBIX" is get printed?
#include<stdio.h>
int main()
{
    int x;
    for(x=-1; x<=10; x++)
    {
        if(x < 5)
            continue;
        else
            break;
        printf("IndiaBIX");
    }
    return 0;
}
Infinite times
11 times
0 times
10 times
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
142 comments Page 2 of 15.

Akhil said:   10 years ago
I. Break statement "STOP's" executing the loop.

II. Continue will execute the next instruction.

1st iteration: x = -1.

Process: if (x<5) [condition true] so "continue" executes and control goes to "else" where we break the loop and iterate again.

So the statement actually never gets printed.
(1)

Ram said:   9 years ago
Thank you @Ankit.
(1)

Sri Harsha said:   9 years ago
Continue statement in the loop will not allow to print.

Because when the continue statement encountered by the c compiler it simple goes to the beginning of the loop.

The x gets incremented up to 5 and after that loop will be braked.
(1)

Ashish said:   9 years ago
Once the value of x reaches 5 it executes else part, which is break statement, break statement terminates loop. This means the control will never encounter printf statement. Hence no 'IndiaBix' will be printed.
(1)

Aashiya said:   2 years ago
Their is 5 times india fix is printed before the break of for loop..
(1)

Amit said:   1 decade ago
The continue statement transfers the control to the next iteration in the loop (increment step).

SANDEEP KUMAR SINGH said:   1 decade ago
The first condition is x<5, that's why loop will continue and keep incrementing value of x until x=5.

When x=5 then condition will go to else part and since break statement is there it will come out of loop.

So, it is not going to print "IndiaBIX".

Manya said:   1 decade ago
Thank you Sandeep.

Himani said:   1 decade ago
Thanks all of you. You all have cleared my doubt.

Vignatha said:   1 decade ago
Ya after the continue and break stmts nxt part o code z nt xcuted n goes to iteration, for that der z no output.


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