C Programming - Const - Discussion

Discussion Forum : Const - Find Output of Program (Q.No. 10)

Const

10.

What will be the output of the program?

#include<stdio.h>

int main()
{
    const c = -11;
    const int d = 34;
    printf("%d, %d\n", c, d);
    return 0;
}

Error

-11, 34

11, 34

None of these

Answer: Option

Explanation:

Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".

Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'.

Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed.

Hence the output of the program is -11, 34

Discussion:

20 comments Page 2 of 2.

G Pavan Kumar said: 10 years ago

7 24 [Error] 'c' was not declared in this scope.

Shahrukh said: 1 decade ago

Ya it will take int as the default data type.

Sandeep said: 1 decade ago

It is giving error C does not name a type.

Chandradeep S said: 8 years ago

In GCC, its's printing some garbage value.

Nakul said: 8 years ago

Why only int and what is constant exactly?

Saravana kumar said: 8 years ago

In c++ shell compiler. It shows an error.

Dinesh said: 1 decade ago

What will be the data type of "c"?

Ram said: 9 years ago

How it will take int data type?

Madhusudan said: 1 decade ago

By default it takes int.

Soumya said: 1 decade ago

Thanks Sunil.

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