C Programming - Const - Discussion
Discussion Forum : Const - Find Output of Program (Q.No. 10)
10.
What will be the output of the program?
#include<stdio.h>
int main()
{
const c = -11;
const int d = 34;
printf("%d, %d\n", c, d);
return 0;
}
Answer: Option
Explanation:
Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".
Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'.
Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed.
Hence the output of the program is -11, 34
Discussion:
20 comments Page 1 of 2.
XYZ said:
1 decade ago
In statement const c = -11, c will be declared as what data type. ?
Madhusudan said:
1 decade ago
By default it takes int.
Shahrukh said:
1 decade ago
Ya it will take int as the default data type.
Sunil kumar patel said:
1 decade ago
If we write that const d=-12; d will be treated as int data type. By default const is int data type.
Soumya said:
1 decade ago
Thanks Sunil.
Arup said:
1 decade ago
If we write const d=12.34
Then what will be the output ?
Can anyone help me?
Then what will be the output ?
Can anyone help me?
Vinod Kr. Rai said:
1 decade ago
@arup.
If we write const d=12.34
Then d By default treated as int data type and it store 12
Example:
#include<stdio.h>
int main()
{
const c = 12.34;
const int d = 34;
printf("%d, %d\n", c, d);
return 0;
}
Output:
12, 34
If we write const d=12.34
Then d By default treated as int data type and it store 12
Example:
#include<stdio.h>
int main()
{
const c = 12.34;
const int d = 34;
printf("%d, %d\n", c, d);
return 0;
}
Output:
12, 34
Dinesh said:
1 decade ago
What will be the data type of "c"?
Amish said:
1 decade ago
In statement const c = -11
c will be declared as what data type ?
And how?
c will be declared as what data type ?
And how?
Arafath Iyman said:
1 decade ago
#include<stdio.h>
int main()
{
const c = "araf";
const int d = 34;
printf("%s, %d\n", c, d);
return 0;
}
output : araf, 34
So it c is of any type.
int main()
{
const c = "araf";
const int d = 34;
printf("%s, %d\n", c, d);
return 0;
}
output : araf, 34
So it c is of any type.
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