C Programming - Const - Discussion
Discussion Forum : Const - Find Output of Program (Q.No. 10)
10.
What will be the output of the program?
#include<stdio.h>
int main()
{
const c = -11;
const int d = 34;
printf("%d, %d\n", c, d);
return 0;
}
Answer: Option
Explanation:
Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".
Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'.
Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed.
Hence the output of the program is -11, 34
Discussion:
20 comments Page 1 of 2.
Osama Siddiqui said:
6 years ago
I am getting an error: 'c' does not name a type. Can anyone tell me why I am getting this error?
Chandradeep S said:
7 years ago
In GCC, its's printing some garbage value.
Akshay said:
7 years ago
The const values become int by default, not any one can be default.
Saravana kumar said:
7 years ago
In c++ shell compiler. It shows an error.
Nakul said:
8 years ago
Why only int and what is constant exactly?
Sarath govind said:
8 years ago
In g++ compiler, it showing error as 'c' was not declared in this scope.
Can anyone help me?
Can anyone help me?
Ram said:
8 years ago
In C++ Shell compiler, it is treated as an error.
What should I do?
What should I do?
Ram said:
8 years ago
How it will take int data type?
G Pavan Kumar said:
9 years ago
7 24 [Error] 'c' was not declared in this scope.
Sandeep said:
9 years ago
It is giving error C does not name a type.
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