C Programming - Command Line Arguments - Discussion
Discussion Forum : Command Line Arguments - Find Output of Program (Q.No. 16)
16.
What will be the output of the program (sample.c) given below if it is executed from the command line?
cmd> sample 1 2 3
cmd> sample 2 2 3
cmd> sample 3 2 3
cmd> sample 1 2 3
cmd> sample 2 2 3
cmd> sample 3 2 3
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
printf("%s\n", argv[0]);
return 0;
}
Discussion:
14 comments Page 1 of 2.
Aman said:
1 decade ago
Can any one explane please?
Nandhakumar said:
1 decade ago
Argv[0]=sample, no matter how many times you are called all are got overwritting.
Anshi said:
1 decade ago
Please. If some one know it then explain it.
Shivu said:
1 decade ago
Please tell me why sample 123 wrong.
Nandu said:
1 decade ago
Here argv[0]=sample, If he will give argv[1] then what will be the answer.
Santhoshi said:
1 decade ago
Hi friends here if want to print only argv[0] so that you print only sample suppose we want to print argv[1] then we print definitely 1 2 3.
Soujanya said:
1 decade ago
argv[0] = sample and also see that %s specifies string not integer.
Athul said:
1 decade ago
Here sample is the first argument so in each line of the command prompt we are calling sample 1 and printing it.
Hareesh naidu said:
10 years ago
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
printf("%s\n", argv[0]);
return 0;
}
In this problem we need to enter cmd> sample 1 2 3 this so here count is incremented argv[0] is sample, argv[1] is 1, argv[2] is 2.
And argv[3] is 3, so we want to printf argv[0] only so the string sample is printed by indexed wise.
#include<stdio.h>
int main(int argc, char *argv[])
{
printf("%s\n", argv[0]);
return 0;
}
In this problem we need to enter cmd> sample 1 2 3 this so here count is incremented argv[0] is sample, argv[1] is 1, argv[2] is 2.
And argv[3] is 3, so we want to printf argv[0] only so the string sample is printed by indexed wise.
Ravikanth said:
9 years ago
argv[0] it means take the first cmd prompt line sample 1 2 3
argv[0]=sample
argv[1]=1 so on
if you take next command line sample 1 2 3
+argv[0]= sample
+argv[1]=1 so on
similiar same third command line also
But our program print{argv[0]=sample}
So, the answer is sample.
argv[0]=sample
argv[1]=1 so on
if you take next command line sample 1 2 3
+argv[0]= sample
+argv[1]=1 so on
similiar same third command line also
But our program print{argv[0]=sample}
So, the answer is sample.
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