C Programming - Command Line Arguments
Exercise :: Command Line Arguments - Find Output of Program
| 1. |
What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog one two three
/* myprog.c */
#include<stdio.h>
int main(int argc, char **argv)
{
printf("%c\n", **++argv);
return 0;
}
|
| A. |
myprog one two three | | B. |
myprog one | | C. |
o | | D. |
two |
Answer: Option C
Explanation:
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| 2. |
What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog one two three
/* myprog.c */
#include<stdio.h>
#include<stdlib.h>
int main(int argc, char **argv)
{
printf("%s\n", *++argv);
return 0;
}
|
Answer: Option B
Explanation:
|
| 3. |
What will be the output of the program (sample.c) given below if it is executed from the command line (Turbo C in DOS)?
cmd> sample 1 2 3
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
int j;
j = argv[1] + argv[2] + argv[3];
printf("%d", j);
return 0;
}
|
Answer: Option C
Explanation:
Here argv[1], argv[2] and argv[3] are string type. We have to convert the string to integer type before perform arithmetic operation.
Example: j = atoi(argv[1]) + atoi(argv[2]) + atoi(argv[3]);
|
| 4. |
What will be the output of the program (sample.c) given below if it is executed from the command line (turbo c under DOS)?
cmd> sample Good Morning
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
printf("%d %s", argc, argv[1]);
return 0;
}
|
| A. |
3 Good | | B. |
2 Good | | C. |
Good Morning | | D. |
3 Morning |
Answer: Option A
Explanation:
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| 5. |
What will be the output of the program #include<stdio.h>
void fun(int);
int main(int argc)
{
printf("%d ", argc);
fun(argc);
return 0;
}
void fun(int i)
{
if(i!=4)
main(++i);
}
|
Answer: Option B
Explanation:
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