C Programming - Command Line Arguments - Discussion

Thank you @Rohan.

Good explanation @Shalini.

@All.

#include<stdio.h>
void fun(int);

Step 1: a function named as fun, takes an integer as argument and return void data type.

int main(int argc)
{
printf("%d ", argc);

Step 2: It will print by default 1 because argc always take atleast 1 argument in the command line arguments..

fun(argc);

Step 3: call the function fun with value 1 [i.e. fun(1);]

return 0;
}

void fun(int i)
{
if(i!=4)
main(++i);

Step 4: -> First Time: if (1!=4)
main(++1) [main(2)]
-> control is transfer to main function with arguement 2
-> prints 2 and so on............
}

Answer will be 2, 3, 4. Option C is the correct one.

Because main() is also a function where the program will start.

But how we can call main from other function?

argc is 1 because default takes one command line argument that is a.out, a.out is one file.

Why argc is 1?

It is showing the answer as 2 3 4 in turbo C.

@Learner, when we execute the program after compiling we give a.out, so the value of argc==1.

That's why the value of argc is 1.