C Programming - Command Line Arguments - Discussion

Is there any differences between **++argv and *++argv?

This program will print an output on both environment Linux/windows-and I think we can define an array size using either variable/macros/const.

As I've tried to define the max as shown:

int max =20;
C Const int max=20; ------------- and it works on both cases.

So may be the error depends on the standard ANSCI CS99 etc.

Friends.

The array has a continue memory allocation also. The array index start with zero is going on.

So the Friday store in array memory just like that start with zero.

So f contain a a[0]=f; a[1]=r; a[2]=i, a[_]=y; so the print "r";

Friends please justify the answer.

argv[1] means Friday.

When we increment pointer by one it will point to r.

Whats the difference between *++argv and **+argv?

argv[0] means " myprog ".

argv[1] indicates "Friday".

++argv[1] means = "riday".

It just point to the next character of f .
Here %c is given so only one character "r".

Will print if there were %s then "riday".
Would print,

printf("%c", *++argv[1]);

It prints "r".

argv[1] is the base address of friday. And on incrementing the base address by will point to r because arg[] is a character pointer.

Hi guys....

++argv=friday & ++argv[1]=r
so the output is correct

@pradeep

int main(int argc,char *argv[])
here argc is total no argument you have passed through
command line argument and argv is an array of pointers which hold all pointers to the arguments which you have passed.
for ex my prog.c is a source file. after compilation you got myprog.exe file(lets say if you dont use other file name then you will get ./a.out file by default).
now we type myprog.exe apple orange
then argc=3
argv[0]=myprog.exe
argv[1]=apple
argv[2]=orange.

regards

Can,any one explain wat is difference between argc and argv?and wat operation it performs in program?with example....