C Programming - Command Line Arguments - Discussion
Discussion Forum : Command Line Arguments - Find Output of Program (Q.No. 15)
15.
What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog one two three
cmd> myprog one two three
/* myprog.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
int i;
for(i=1; i<argc; i++)
printf("%c", argv[i][0]);
return 0;
}
Discussion:
8 comments Page 1 of 1.
Jogamohan Medak said:
1 decade ago
argv[0]=Base address=myprog
argv[1]=One
argv[2]=Two
argv[3]=Three
Given i=1;i<4; i++;
So,argv[1][0]=O(from One )
argv[2][0]=T(from Two )
argv[3][0]=T(from Three )
So Result=ott;
argv[1]=One
argv[2]=Two
argv[3]=Three
Given i=1;i<4; i++;
So,argv[1][0]=O(from One )
argv[2][0]=T(from Two )
argv[3][0]=T(from Three )
So Result=ott;
(1)
Nandhakumar said:
1 decade ago
Here i=1, so argv[i][0]=argv[1][0]=o.
Now i incremented i=2, so argv[i][0]=argv[2][0]=t.
Again i incremented i=3, so argv[i][0]=argv[3][0]=t.
So ott.
Now i incremented i=2, so argv[i][0]=argv[2][0]=t.
Again i incremented i=3, so argv[i][0]=argv[3][0]=t.
So ott.
(1)
Mayank said:
8 years ago
Shouldn't it show error as argv is 1d array and we are trying to access argv[][];?
Malathie said:
8 years ago
Clear explanation Thanks @Jogamohan Medak.
SAGAR said:
8 years ago
Nice solution, Thanks @Nandhakumar.
Azagumozhi said:
9 years ago
Nice explanation @Nandhakumar.
Praveen said:
8 years ago
Thank you @Nandhakumar.
Merlin said:
1 decade ago
Thanks nandhakumar
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