Biochemical Engineering - Fermentation Reactors

Exercise : Fermentation Reactors - Section 1
26.
A chemostat has a liquid volume of 2 litres and is being fed at a rate of 4 litres per hour. Dilution rate for this reactor will be
2 litres
2 litres per hour
2 h-1
4 litres per hour
Answer: Option
Explanation:
No answer description is available. Let's discuss.

27.
Mixing per unit volume is observed to be poorest in
continuous packed bed reactor
continuous fluidized bed bioreactor
continuous airlift bioreactor
none of the above
Answer: Option
Explanation:
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28.
The growth of an organism on glucose is described by the following Monod model parameters: μm = 0.5 h-1 and Ks =0.1 g.l-1, if the concentration of glucose in the feed is 10 g.l-1 and the dilution rate is set to 0.4 h-1, then the steady state concentration of glucose in the effluent will be
0 g.l-1
0.5 g.l-1
1.0 g.l-1
10 g.l-1
Answer: Option
Explanation:
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29.
A continuous reactor at steady state contains 0.04 g.l-1 of biomass and 0.02 g.l-1 of phenol. The feed contained 0.1 g.l-1 of phenol. The biomass yield would be
0.4 g.g-1
0.5 g.g-1
1.0 g.g-1
5.0 g.g-1
Answer: Option
Explanation:
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30.
A culture system with constant environmental conditions maintained through continual provision of nutrient and removal of wastes is called __________ culture system.
continuous
batch
fed-batch
semi continuous
Answer: Option
Explanation:
No answer description is available. Let's discuss.