Biochemical Engineering - Fermentation Reactors

Exercise :: Fermentation Reactors - Section 1

26. 

A chemostat has a liquid volume of 2 litres and is being fed at a rate of 4 litres per hour. Dilution rate for this reactor will be

A. 2 litres
B. 2 litres per hour
C. 2 h-1
D. 4 litres per hour

Answer: Option C

Explanation:

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27. 

Mixing per unit volume is observed to be poorest in

A. continuous packed bed reactor
B. continuous fluidized bed bioreactor
C. continuous airlift bioreactor
D. none of the above

Answer: Option A

Explanation:

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28. 

The growth of an organism on glucose is described by the following Monod model parameters: μm = 0.5 h-1 and Ks =0.1 g.l-1, if the concentration of glucose in the feed is 10 g.l-1 and the dilution rate is set to 0.4 h-1, then the steady state concentration of glucose in the effluent will be

A. 0 g.l-1
B. 0.5 g.l-1
C. 1.0 g.l-1
D. 10 g.l-1

Answer: Option B

Explanation:

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29. 

A continuous reactor at steady state contains 0.04 g.l-1 of biomass and 0.02 g.l-1 of phenol. The feed contained 0.1 g.l-1 of phenol. The biomass yield would be

A. 0.4 g.g-1
B. 0.5 g.g-1
C. 1.0 g.g-1
D. 5.0 g.g-1

Answer: Option B

Explanation:

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30. 

A culture system with constant environmental conditions maintained through continual provision of nutrient and removal of wastes is called __________ culture system.

A. continuous
B. batch
C. fed-batch
D. semi continuous

Answer: Option A

Explanation:

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