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Biochemical Engineering - Enzymes and Kinetics - Discussion

Discussion Forum : Enzymes and Kinetics - Section 1 (Q.No. 8)
Enzymes and Kinetics
8.
Given an enzyme with a Km = 10m M and Vmax = 100 m mol/min. If [S] = 100 m M, which of the following will be true?
A 10 fold increase in Vmax would increase velocity 10 fold y
A 10 fold decrease in Km would increase velocity
Both (a) and (b)
A 10 fold increase in Vmax would decrease velocity 20 fold
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.
Fatin raza khan said:   1 decade ago
C is most probable answer because v=vmax.s/km+s, m.m equation.

v is directly proportional and km is inversely proportional.
Prareeta Mahapatra said:   8 years ago
10 fold decrease in km means the km'=10 km (bcoz affinity = 1/km not only km), so we will increase so the second statement is false and the answer should be the option (A).
Manisha said:   8 years ago
V = vmax|S|/km+|s| do if we increase v max v increase and decrease km will also increase v. If km is small it means affinity high so more substrate bind to the enzyme.
Ravi Saini said:   7 years ago
I think C is the answer because the decrease in Km also leads to increase in velocity (formula- V= (Vmax*S)/(Km+S).
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