Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
60 comments Page 3 of 6.

Venki said:   1 decade ago
Yes its a cylinder but it has 1 mm wall thickness. So we calculate the weight of iron.

S.Vijay said:   1 decade ago
Tell me the formula of this problem?

Sanoop said:   1 decade ago
How comes 462*8 gm?

Sanjay said:   9 years ago
1 hectares is equal to how many cm cube?

Rajadurai said:   9 years ago
Why [4]^2 - [3]^2 while calculating volume?

Anyone please explain this step.

Thuru said:   9 years ago
I don't understand this.

Is there any easy way to understand this?

Avani said:   9 years ago
Same doubt @Rajadurai.

Sibi said:   9 years ago
@Divya as per formula, it means cylinder volume is,

pi*r^2h, here it is a hollow cylinder we have to subtract external diameter to internal diameter.

Sai dileep said:   9 years ago
What is the formula for calculating the volume of this problem?

Aliza mir said:   9 years ago
@Sai Dileep. The formula for volume to be applied here is the cylinder.

@Rajadurai. Since the pipe is hollow so the internal part is being subtracted from the total thickness, which is the radius.


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