Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
60 comments Page 2 of 6.

Akanksha said:   1 decade ago
How the internal radius comes ?

Praveen Singh said:   1 decade ago
Akanksha External Radius=4 and in problem thickness=1, then Internal radius=4-1=3.thats hit...

Preeti said:   1 decade ago
Can some one explain how thickness and external radius are related. I understood we have to subtract but why?

Nats said:   1 decade ago
External radius - thickness = internal radius.

VINU said:   1 decade ago
Why subtract external radius to internal radius?

DR Sharma said:   1 decade ago
Internal radius is subtracted from the external radius to find out the volume of hollow pipe.

Venugopal said:   1 decade ago
Can you tell me the formula for Volume of iron?

Shivani said:   1 decade ago
Why there is need to multiply by 22/7?

Sahi said:   1 decade ago
@Shivani.

22/7 is the value of pi. Used in calculating volume of cylinder = pi*r^2*h.

Tejas said:   1 decade ago
What is iron pipe here?

Is it volume of cylinder?


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