Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
60 comments Page 4 of 6.

Albin Antony said:   9 years ago
Volume = base area * height.

For calculating, base area of the given hollow cylinder, we should remove the area containing thickness from the original.

So (pi * 4^2) - (pi*3^2) = pi* (4^2 - 3^2) = Effective base area.

Nagi said:   9 years ago
Why diameter is converted into radius?

Nagi said:   9 years ago
Please anyone say why we are taking radius instead of diameter?

Manasa said:   9 years ago
Diameter d = 2r.

Tomsy said:   9 years ago
Please, someone explain me by step by step.

Ravi said:   8 years ago
Surface area of iron cube of side 10cm is?

Junaid said:   8 years ago
Why is the internal radius 3cm?

Suba sanjeev .m said:   8 years ago
I am not getting this, can you explain clearly?

Utham said:   8 years ago
The Internal radius and external radius. given is 8g/cm^3 not for hollow space.So, the first find out the full volume that is with the use of external radius. Now subtract hollow space that volume with internal radius. R^2h*r^2h.

Ajay said:   8 years ago
Could you explain me about pi?


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