Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 7)
7.
50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m3, then the rise in the water level in the tank will be:
Answer: Option
Explanation:
Total volume of water displaced = (4 x 50) m3 = 200 m3.
 Rise in water level = |
 |
200 |  m 0.25 m = 25 cm. |
| 40 x 20 |
Discussion:
26 comments Page 3 of 3.
Nihar said:
5 years ago
Shouldn't we consider the actual height and raised height here?
Shiva Prasad said:
5 years ago
How 0.25 came? Explain it.
Khushi said:
5 years ago
How it is 0.25? I don't understand clearly, plz explain it once.
Nisma said:
5 years ago
@Khushi.
By calculating h, we get;
h=200/20*40,
= 1/4,
= 0.25.
By calculating h, we get;
h=200/20*40,
= 1/4,
= 0.25.
Bavithra said:
4 years ago
Why not we consider a cylindrical shape tank? Then the volume for the cylinder is different.
Dhanya said:
4 years ago
@Bavithra.
We consider the shape of the tank to be a cuboid as in the question it is given that the tank is 40m long and 20m broad. Here length and breadth are given, which indicates that the tank is cuboidal in shape.
We consider the shape of the tank to be a cuboid as in the question it is given that the tank is 40m long and 20m broad. Here length and breadth are given, which indicates that the tank is cuboidal in shape.
(1)
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