Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 7)
7.
50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m3, then the rise in the water level in the tank will be:
Answer: Option
Explanation:
Total volume of water displaced = (4 x 50) m3 = 200 m3.
 Rise in water level = |
 |
200 |  m 0.25 m = 25 cm. |
| 40 x 20 |
Discussion:
26 comments Page 2 of 3.
Salini said:
9 years ago
Thank you very much @Deepak.
Swarna said:
9 years ago
Displacement of water by 1 man = 4 m3.
Total volume of water displaced by 50 men = (4 x 50) m3 = 200 m3.
Rise in water level in the tank is same as the height of the volume of cuboid.
Volume = Length x Breadth x Height.
Rise in water level = 200/(40 x 20) = 0.25 m or 25 cm.
Total volume of water displaced by 50 men = (4 x 50) m3 = 200 m3.
Rise in water level in the tank is same as the height of the volume of cuboid.
Volume = Length x Breadth x Height.
Rise in water level = 200/(40 x 20) = 0.25 m or 25 cm.
(15)
Praveen said:
8 years ago
Nice explanation. Thanks @Swarna.
TAMIL MANI SELVAM said:
8 years ago
Guys could anyone explain me.
How they find rise in water level = volume/(l*b)?
Whether any formula is there to find out rise of water level?
How they find rise in water level = volume/(l*b)?
Whether any formula is there to find out rise of water level?
(1)
Akhil said:
8 years ago
Thanks @Swarna.
Nikhita said:
8 years ago
Why should we consider the shape as cuboid?
Sachin said:
7 years ago
Why it is mentioned as m^3?
(1)
Suvani said:
6 years ago
Which shape of tank will be considered.
(1)
Padma said:
6 years ago
Thanks @Swarna.
Maneesha said:
5 years ago
Thank you @Swarna.
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