Aptitude - True Discount - Discussion
Discussion Forum : True Discount - General Questions (Q.No. 11)
11.
Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?
Answer: Option
Explanation:
S.I. on Rs. (260 - 20) for a given time = Rs. 20.
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
 T.D. on Rs. 260 = Rs. |
 |
10 | x 260 |  |
= Rs. 10.40 |
| 250 |
Discussion:
24 comments Page 1 of 3.
Smitha said:
4 years ago
T.D = 20
Amount = 260
P.w = Amount - TD = 240.
S.I on p.w = 20.
By formula:
R * T = S.I * 100/p.w = 25/3.
Again by question:
Td = p.w * R * T/100.
Where the Time is half so R*T/2.
i.e 25/6.
We get TD = 10.49.
Amount = 260
P.w = Amount - TD = 240.
S.I on p.w = 20.
By formula:
R * T = S.I * 100/p.w = 25/3.
Again by question:
Td = p.w * R * T/100.
Where the Time is half so R*T/2.
i.e 25/6.
We get TD = 10.49.
(2)
Nagaraj said:
1 decade ago
Case 1:
PW would be (260-20) = 240.
20 = 240xrxt.
rt = 1/12.
case 2:
Sum due = 260, let's take true discount be 'X'.
PW = 260-X.
t = t/2 => rt = 1/24.
X = (260-X) x 1/24
25X = 260
X = 10.4.
T.D = 10.4.
PW would be (260-20) = 240.
20 = 240xrxt.
rt = 1/12.
case 2:
Sum due = 260, let's take true discount be 'X'.
PW = 260-X.
t = t/2 => rt = 1/24.
X = (260-X) x 1/24
25X = 260
X = 10.4.
T.D = 10.4.
(2)
Poonam yadav said:
9 years ago
I am unable to understand these type of questions. Can anyone please explain more?
Rda said:
3 years ago
Thanks @Wasim Ajaz.
Abi said:
4 years ago
@Smitha.
I am getting 10 as answer.
I am getting 10 as answer.
Pavan G J said:
5 years ago
It is correct, just take rt/100 = 1/24.
Shawn Soares said:
5 years ago
How are you all calculate RT to be 1/12, by using TD=PW*(RT)?
Shouldn't the formula be TD=PW*(RT)/100? Which should give RT=100/12?
Shouldn't the formula be TD=PW*(RT)/100? Which should give RT=100/12?
Manish Kumar said:
6 years ago
@Somesh Saurabh,
Your explanation really helped us, but could anyone correct me if im wrong:
that is why divide by 100 is Missing:
i.e, SI = P*R*T/100.
so, SI on TD = (Amount - TD *R*T)/100.
Your explanation really helped us, but could anyone correct me if im wrong:
that is why divide by 100 is Missing:
i.e, SI = P*R*T/100.
so, SI on TD = (Amount - TD *R*T)/100.
Vaishali jagtap said:
7 years ago
I am not getting it. Please help it with the correct explanation.
Wasim Ajaz said:
7 years ago
Here's the correct way,
Td=20,A=260,pw=240,
Td=pw * rt ÷ 100; rt=100/12.
ATQ, time is reduced to half so new time(rt2) will b 100/24.
Td=a * rt2/100+rt2;
Td=(260 * (100/24))÷ (100+100/24) = 10.4.
Td=20,A=260,pw=240,
Td=pw * rt ÷ 100; rt=100/12.
ATQ, time is reduced to half so new time(rt2) will b 100/24.
Td=a * rt2/100+rt2;
Td=(260 * (100/24))÷ (100+100/24) = 10.4.
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