Aptitude - True Discount - Discussion
Discussion Forum : True Discount - General Questions (Q.No. 11)
11.
Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?
Answer: Option
Explanation:
S.I. on Rs. (260 - 20) for a given time = Rs. 20.
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
 T.D. on Rs. 260 = Rs. |
 |
10 | x 260 |  |
= Rs. 10.40 |
| 250 |
Discussion:
24 comments Page 1 of 3.
Pooja said:
1 decade ago
Please elaborate the explanation.
Kuldeep said:
1 decade ago
Please explain this answer.
Shivam said:
1 decade ago
Please explain how this method is wrong
Amount is 260
PW would be (260-20)=240
20=240xrxt/100
rt=100/12
if t=t/2
TD=240 x r x t/2 x r/100
TD=240 x 100/2400
TD=10
Amount is 260
PW would be (260-20)=240
20=240xrxt/100
rt=100/12
if t=t/2
TD=240 x r x t/2 x r/100
TD=240 x 100/2400
TD=10
Shivam said:
1 decade ago
How simple interest is different from True Value, it seems both are same.
Please give example of both.
Please give example of both.
Anshika said:
1 decade ago
I am unable to understand such type of ques, SI & CI ques, I can solve but there occur many problems when I solve it, please tell me easy of understand such type of questions.
Thanks.
Thanks.
LARA said:
1 decade ago
First we have to find the value of (R*T) using the formula for PRESENT WORTH.
AMT = PRESENT WORTH + TRUE DISCOUNT.
Then calculate the value for (T/2) i.e., (R*T)/2, using this value and the same amount calculate the new PRESENT WORTH.
AMT = PRESENT WORTH + TRUE DISCOUNT.
Then calculate the value for (T/2) i.e., (R*T)/2, using this value and the same amount calculate the new PRESENT WORTH.
Nagaraj said:
1 decade ago
Case 1:
PW would be (260-20) = 240.
20 = 240xrxt.
rt = 1/12.
case 2:
Sum due = 260, let's take true discount be 'X'.
PW = 260-X.
t = t/2 => rt = 1/24.
X = (260-X) x 1/24
25X = 260
X = 10.4.
T.D = 10.4.
PW would be (260-20) = 240.
20 = 240xrxt.
rt = 1/12.
case 2:
Sum due = 260, let's take true discount be 'X'.
PW = 260-X.
t = t/2 => rt = 1/24.
X = (260-X) x 1/24
25X = 260
X = 10.4.
T.D = 10.4.
(2)
Harini said:
1 decade ago
How S.I and true discount equal?
Aparna said:
1 decade ago
ptr/100 = SI.
240*tr = 2000.
Then tr = 2000/240.
Then how did you got that 1/12?
Please tell me.
240*tr = 2000.
Then tr = 2000/240.
Then how did you got that 1/12?
Please tell me.
Shivangi said:
1 decade ago
What is SI?
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