Aptitude - True Discount - Discussion
Discussion Forum : True Discount - General Questions (Q.No. 10)
10.
The present worth of Rs. 2310 due 2
years hence, the rate of interest being 15% per annum, is:

Answer: Option
Explanation:
P.W. = Rs. | ![]() |
100 x 2310 | ![]() |
= Rs. 1680. | ||
|
Discussion:
21 comments Page 1 of 3.
Satish said:
1 decade ago
How did you get the 5/2?
Farhaan said:
1 decade ago
Elaborate explanation (step by step).
Nikitha said:
1 decade ago
5/2 is equivalent to 2 n 1/2 years.
Kishan said:
1 decade ago
What equations are apply the above problem to get solution. Please solve my dout.
Www said:
1 decade ago
GIVEN AMOUNT=2310/-
TIME=2 AND 1/2 MEANS 24+6 months=30/12 years=5/2 years
R=15%
Thus using the formula of P.W
P.W=(amount*100)/(100+[R*T])
TIME=2 AND 1/2 MEANS 24+6 months=30/12 years=5/2 years
R=15%
Thus using the formula of P.W
P.W=(amount*100)/(100+[R*T])
Mozthi said:
1 decade ago
How did you get the 5/2? how it possible to solve the problem. Please clear my dought?
L.mayuran said:
1 decade ago
Given amount- 2310/=
Present value- 2310/(1.15^2.5)
Answer is 1628.79/=
Present value- 2310/(1.15^2.5)
Answer is 1628.79/=
Hari said:
1 decade ago
How did you solve 1.15^2.5??
Rajee said:
1 decade ago
Here, they have given the total amount (i.e. interest+principal) after 2 and 1/2 years = 5/2.
Simple interest = (principal*num of years*rate of interest)/100.
Total amount = simple interest & principal.
2310 = (pnr/100)+p.
2310 = p[(nr/100)+1].
231000 = p[((5/2)*15)+100].
(Since,multiply 100 on both sides).
Therefore, p = (231000*2)/[(5*15)+200].
Present worth p = 1680 rupees.
Simple interest = (principal*num of years*rate of interest)/100.
Total amount = simple interest & principal.
2310 = (pnr/100)+p.
2310 = p[(nr/100)+1].
231000 = p[((5/2)*15)+100].
(Since,multiply 100 on both sides).
Therefore, p = (231000*2)/[(5*15)+200].
Present worth p = 1680 rupees.
Atik said:
1 decade ago
P.W means?
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