Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
371/2
40 days
Answer: Option
Explanation:

Whole work is done by A in ( 20 x 5 ) = 25 days.
4

Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15

Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75

So, B alone would do the work in 75 = 37 1 days.
2 2

Discussion:
164 comments Page 11 of 17.

Inna said:   10 years ago
A's work 80% --- 20.

100% --- 25 (A).

A + B work (the remaining work means) 20% --- 3.

100% --- 15 (A+B).

(A+B) - A = B.

= 25*15/10 = 75/2 = 37*1/2.

Punitsw said:   10 years ago
In simple words:

A completes 80% in 20 days so would 92% in 23 days.

Remaining 8% completed by B in 3 days (21 - 23rd).

Now if B completes 8% in 3 days. So will be able to complete 100% in 37.5 days (3 x 100/8).

SUJALA said:   10 years ago
A is doing 80% work in 20 days.

80/100 = 20.

4/5 = 20/1 (cross multiplication).

= 25 days.

It means a can take time to complete 100% of work for 25 days.

A+B is doing 20% of work in 3 days.

= 20/100 = 3/1 (cross multiplication) = 15 days.

Now B to get complete 100% of work is?

(A+B)-A = B.

= 1/15-1/25 = 2/75 = 37*1/2.

Sivapriya said:   10 years ago
Hai guys I have one doubt. Will you please explain me. Geore do 3/5th work in 9 days. He then call paul and finish in 4 days. How long paul take to work by himself?

Atyanand said:   10 years ago
A complete 80% work in 20 days.

So A complete 100% work in 25 days.

Work done by A in 1 day = 1/25......equation (1).

A+B complete 20% work in 3 days.

So, A+B complete its 100% work in 15 days.

Work done by A+B in 1 day = 1/15.

From equation 1.

B = 1/15-1/25 = 2/75.

Kannan said:   10 years ago
I don't understand please explain.

Sonam said:   10 years ago
My method:

A's one day work = 80/100*1/20 = 1/25.

A+B together = 20/100*1/3 = 1/15.

B's one day work = (A+B)-A.

1/15-1/25 ---> now take LCM and solve.

You will get 2/75 i.e., 75/2 days.

Hope this helps you.

Aravind said:   10 years ago
For A 80% of work = 20 days.

100% of work = x?

Cross multiple:

x = 20*100/80.
x =25 days.

A 1 days work = 1/25....(1).

For a and b together 20% of work = 3 days.

100% of work = x?

Cross multiple x = 15 days.

A 1 day work + b 1 day work = 1/15.

1/25+ b 1 day work = 1/15.

B 1 day work = 1/15-1/25 = 2/75.

B Can complete in 75/2 = 37 1/2.

Gaurav gupta said:   1 decade ago
Here is the solution to get total work days of A.

80% work can done in 20 days.

So 1% can be done in (20/80%) = (20/80)*100 = 25 days.

Srini said:   1 decade ago
A's 20% work in 5 days and A+B'in 3 days,

So B's 20 work in (1/3 - 1/5) = 2/15 i.e 15/2.

So B's 100% work in (15/2)*5 = 75/2 = 37.5 days.


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