Aptitude - Time and Work - Discussion

Now total work=30 units.

A + B complete the 30 units of work in 30 days.

So, in one day they together complete 1 unit of work.

In 20 days, they complete 20 units of work.

Agree?

Now remaining work is 30 units-20 units=10 units is remaining which will be completed by A.

A takes 20 days to complete the remaining 10 units of work.
So he does 10/20= 1/2 unit of work in one day.
If A completes 1/2 unit of work in one day, then how many days he will take to complete the entire 30 units of work?

30/ (1/2) = 60 days.

E * t = w.

Since e is inverse of t so 20 becomes 1/20.
Now 1/20*t=1/3 since we have to find the time taken so,
T =20/1/3 HENCE T= 60 because in LHS it is multiplication so after coming to RHS it will divide.

Please, Explain this with LCM method.

Can anyone explain this with LCM method?

Nice. Thanks all for explaining.

Together 1/30*20=2/3.
2parts work completed.
Remaining 1 part 'A'completed in 20days.
1part work 20days.
3 prts --------?.
3 * 20 = 60 days.

Good job @Kaaly.

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