Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 10)
10.
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?
11:30 A.M.
12 noon
12:30 P.M.
1:00 P.M.
Answer: Option
Explanation:

(P + Q + R)'s 1 hour's work = ( 1 + 1 + 1 ) = 37 .
8 10 12 120

Work done by P, Q and R in 2 hours = ( 37 x 2 ) = 37 .
120 60

Remaining work = ( 1 - 37 ) = 23 .
60 60

(Q + R)'s 1 hour's work = ( 1 + 1 ) = 11 .
10 12 60

Now, 11 work is done by Q and R in 1 hour.
60

So, 23 work will be done by Q and R in ( 60 x 23 ) = 23 hours = 2 hours.
60 11 60 11

So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.

Discussion:
95 comments Page 6 of 10.

Piyus said:   1 decade ago
Friends

P's 2 hr work = 1/8*2=1/4
rest 3/4 work done by q&r
q+r 1hr = 1/10 + 1/12=11/60 work
3/4 work by q&r=60/11 * 3/4=4.09

The work complete time was 9a.m+4=1p.m

Janie said:   5 years ago
The solution is;

10 - 8=2
12 - 10=2
So, two is a common difference.
Then, P is closed at 11:AM.
11:00 + 00:30 = 11:30.
Continued for four good times then you'll get 1:00PM.

Sameer said:   1 decade ago
P 1hrs work 1/8
Q 1hrs work 1/10
R 1hrs work 1/12

p worked for 2 hrs so 2*1/8
suppose Q and r worked for 'x' hrs
then,
2*1/8+(1/10)*x+(1/12)x = 1
x=4.09
ans 9+4.09 = 1pm
(1)

Ramkumar said:   1 decade ago
Can anyone tell

Why you put last step as 9am+4?

Already p, q, r done by 2hrs and (q&r) in 4 hrs know.

Then 2+4=6 only know.

On this step I am in confusion. Help me.

Deepak said:   1 decade ago
A and B can done a work in 10 days, B and C done same work in 18 days,

If A did work 4 days, B did 8 days and C did 14 days. How much days C takes to complete same work?

Ashna said:   1 decade ago
P in 1 hr-----1/8.
Q in 1 hr-----1/10.
R in 1 hr-----1/12.

Therefore 2/8+(x+2)/10+(x+2)/12 = 1.

On solving x=23/11=2 hrs. (approx).

Therefore, 11 A.M.+2hr = 1 P.M.

Balu said:   10 years ago
Hello guys, easy solution:

X-2/8 + X/10 + X/12 = 1 (lik A+B+C's 1 Day Work).

By solving we get X = 4.

So, Machines are started at 9.

= 9+4 = 13 (i.e, 1'O clock).

Div said:   1 decade ago
Since machine p stops after 37 units of work is completed from 60 units of work, still (60-37=23) 23units of work is remaining. hence, 1-(37/60)= 23/60

Jyothi.k said:   1 decade ago
@Sowjanya

11/60 work done by q and r in i hour

Therefore

1 work done by q and r in 60/11 hour

So 23/60 work done by q and r in 60/11*23/60 hours

K.anusha said:   1 decade ago
Please I can't get the answer this last step please friends will explain to me.

How will come to this is 3/4 can you explain to me friends please.


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