Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
60 | 15 |
Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Discussion:
344 comments Page 32 of 35.
Sheelu said:
1 decade ago
1/15+1/20=7/60
7/60*4=8/15
7/60*4=8/15
Sunil jat kantia said:
1 decade ago
Please solve this problem.
Pooja said:
8 years ago
Why we subtract 7/15 by 1?
Sajid said:
6 months ago
(+1-7/15).
(-*-=+) = 8/15.
(-*-=+) = 8/15.
(3)
Beer ibrahim said:
1 decade ago
Why (1-7/15) is applied ?
(1)
Asshok said:
9 years ago
Why 1 - 7/15? Explain it.
Sagar said:
8 years ago
How to 300 come? Explain.
Gowtham said:
1 decade ago
How came remaining days?
Santhi said:
1 decade ago
Good explanation swetha.
Aadesh said:
8 years ago
28/60=14/30=7/15 @Pooja.
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