Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
344 comments Page 23 of 35.

Ashwini said:   10 years ago
Its very simple 1/1-7/15.

LCM between 1 and 15 is 15.

So = (1/1)*(15/15) - (7/15)*(1/1) {Make both the denominator as 15 i.e LCM}.

= 15/15 - 7/15.

= (15-7)/15 = 8/15.

Hope understood!

Dinesh said:   10 years ago
This problem ok I can understand but some other problems I can't understand my dear friends.

Bhargav said:   10 years ago
I don't understand why we take 1-7/15?

RANGADHAR said:   10 years ago
If the total work is taking the LCM of 15 & 20.

Then it will be 60.

A = 15 days.
B = 20 days.

LCM = 60 work.

Then A do in one day = 60/15 = 4 work.

B = 60/20 = 3 work.

In one day they work = {4+3} work.

In 4 days = 7*4 = 28 works.

Remaining = 60-28 = 32 work.

Then 32/60 = 8/15.

Mohsin said:   10 years ago
How (7/60*4) = 7/15?

Sumit sharma said:   10 years ago
Please some one tell how 1/10:1/15:1/20 comes 6:4:3?

Mitsuna said:   10 years ago
"From the above answer, we can say 15/8 days required to.

Complete the remaining work by A and B".

Can you please calculate this in whole number so that we can assume the exact days remaining?

Sudhansu said:   10 years ago
1-7/15 applied because the whole work is 1.

RPV said:   10 years ago
Why in this sum answer is not reciprocated in time and work problem the answer must be in reciprocal? Ex. 8/15 is written as 15/8 am correct.

RPV said:   10 years ago
Tulsi and Ram can do a job alone in 20 days and 30 days respectively. In how many days the job will be finished if they work together?


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