Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
| A's 1 day's work = | 1 | ; |
| 15 |
| B's 1 day's work = | 1 | ; |
| 20 |
| (A + B)'s 1 day's work = |  |
1 | + | 1 |  |
= | 7 | . |
| 15 | 20 | 60 |
| (A + B)'s 4 day's work = | |
7 | x 4 | |
= | 7 | . |
| 60 | 15 |
| Therefore, Remaining work = | |
1 - | 7 | |
= | 8 | . |
| 15 | 15 |
Discussion:
351 comments Page 20 of 36.
Amrinder said:
2 decades ago
4/60 is ok 4 is no of working and 60 is hours in day
cant undestand 3/60
cant undestand 3/60
Neha garg said:
1 decade ago
Let total work is 1
1/15+1/20=x/4
7/60*4=x
that means x=7/15
1-7/15=8/15
1/15+1/20=x/4
7/60*4=x
that means x=7/15
1-7/15=8/15
Rashmi said:
1 decade ago
How did you get 7/60 please answer in simple method and tell how got 7.
Fazeena said:
8 years ago
I can't understand 1-7/15.
So, please explain me again or another way.
So, please explain me again or another way.
Sangeetha said:
1 decade ago
Yes swetha your are right. Its very simple and easy method. Thank you.
Prashant Devada said:
9 years ago
@Akash.
You are great, LCM concept makes easy to understand.
Thanks.
You are great, LCM concept makes easy to understand.
Thanks.
Ashik said:
8 years ago
If we calculate A and B 's work together 1/15+1/20 then it will came?
Gurdeep said:
1 decade ago
@Jansi.
Both A and B doing the same (one) work, not different work.
Both A and B doing the same (one) work, not different work.
Sneha said:
8 years ago
Therefore, A + B + C = 36w/13d/w=2*10/13. How is it? please explain.
Lottie said:
2 decades ago
I was thinking 1-7/15 will be 6/15. So how did you get 8/15. Thanx.
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