Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
344 comments Page 19 of 35.

Shruti said:   10 years ago
How 60 came?

Birander yadav said:   10 years ago
1/15+1/20 = 7/60*2 = 7/15.

Total work day = 1-7/15 = 8/15.

Priya said:   10 years ago
Can you explain how this 7/15 came?

Mukesh gautam said:   10 years ago
Simple method:

A-15.
B-20.

LCM is 60.

60/15 = 4.
60/20 = 3.

Total work 60 an total unit work done by a and b is 7.

In q4 day work are done than total 4 day work is 7x4 = 28.

Remaining work 60-28 = 32.

Fraction of remaining work is 32/60 = 8/15. Solution are done in only 20 sec. This method is very simple and less time consuming.

Arafat Neloy said:   10 years ago
A can do a work in 15 days and B in 20 days.

A: 15 days-----1 work.

1 day-------1/15 work.

4 days------4/15 work.

B: 20 days-----1 work.

1 day-------1/20 work.

4 days------4/20 work or 1/5 work.

4/15 + 1/5 = 7/15.

Total work 1.

So, remaining work (1-7/15).

= 8/15 answer.

Niral said:   10 years ago
@Sushmoy.

(1 - 7/15) = 8/15.

Denominator of 1 will be 15 so it will be (15-7/15) = 8/15 will be answer.

Dnyaneshwar said:   10 years ago
1*15 = 15.

15-8 = 7.

So that denominator remains same 7/15.

Sushmoy said:   10 years ago
(1-8/15) = 7/15 how is it possible? Please explain me.

Naren said:   10 years ago
Dear friends, I have the doubt that why we take the total work as 1 instead of taking 60.

We take LCM of 15 & 20 as 60. So we consider 60 units as the total work. So we should take 60? Help me please.

Priya said:   10 years ago
How 7 came please tell me again?


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