Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
| A's 1 day's work = | 1 | ; |
| 15 |
| B's 1 day's work = | 1 | ; |
| 20 |
| (A + B)'s 1 day's work = |  |
1 | + | 1 |  |
= | 7 | . |
| 15 | 20 | 60 |
| (A + B)'s 4 day's work = | |
7 | x 4 | |
= | 7 | . |
| 60 | 15 |
| Therefore, Remaining work = | |
1 - | 7 | |
= | 8 | . |
| 15 | 15 |
Discussion:
345 comments Page 17 of 35.
Basivireddy said:
10 years ago
Hi guys, this is Basivireddy.
A can be work in 15 days = 1/15.
B Can be work in 30 days = 1/30.
1/15 + 1/30.
7/60 this is one day work.
We want 4 days work that's why it is 4*7/60 = 28/60 = 7/15.
Now one day work means they left one day so.
1-7/15 = 8/15, I hope so you understood, Thank you guys, have a great day.
A can be work in 15 days = 1/15.
B Can be work in 30 days = 1/30.
1/15 + 1/30.
7/60 this is one day work.
We want 4 days work that's why it is 4*7/60 = 28/60 = 7/15.
Now one day work means they left one day so.
1-7/15 = 8/15, I hope so you understood, Thank you guys, have a great day.
Harkanwal said:
10 years ago
Why 32 by 60? Explain in detail.
ANI KONAR said:
10 years ago
Short trick:
15, 20 LCM 60.
4, 3 efficiency.
4 + 3 = 7 in 1 day.
7 * 4 = 28 in 4 days.
Remaining = 60 - 28 = 32.
In fraction 32/60 = 8/15.
15, 20 LCM 60.
4, 3 efficiency.
4 + 3 = 7 in 1 day.
7 * 4 = 28 in 4 days.
Remaining = 60 - 28 = 32.
In fraction 32/60 = 8/15.
Mouni said:
10 years ago
A's days = 15.
B's days = 20.
LCM of both = 60 (total work also).
A's work per day = 60/15 = 4.
B's work per day = 60/20 = 3.
Both can do work in one day = (4+3) = 7.
4 days work of both = 7*4 = 28.
Then remaining work = (60-28) = 32.
So please tell me how can I fractionate it?
B's days = 20.
LCM of both = 60 (total work also).
A's work per day = 60/15 = 4.
B's work per day = 60/20 = 3.
Both can do work in one day = (4+3) = 7.
4 days work of both = 7*4 = 28.
Then remaining work = (60-28) = 32.
So please tell me how can I fractionate it?
Keshav said:
10 years ago
Nice explanation.
Shashi kant said:
10 years ago
A's days = 15.
B's days = 20.
LCM of both = 60 (total work also).
A's work per day = 60/15 = 4.
B's work per day = 60/20 = 3.
Both can do work in one day = (4+3) = 7.
4 days work of both = 7*4 = 28.
Then remaining work = (60-28) = 32.
So please tell me how can I fractionate it?
B's days = 20.
LCM of both = 60 (total work also).
A's work per day = 60/15 = 4.
B's work per day = 60/20 = 3.
Both can do work in one day = (4+3) = 7.
4 days work of both = 7*4 = 28.
Then remaining work = (60-28) = 32.
So please tell me how can I fractionate it?
RPV said:
10 years ago
Tulsi and Ram can do a job alone in 20 days and 30 days respectively. In how many days the job will be finished if they work together?
RPV said:
10 years ago
Why in this sum answer is not reciprocated in time and work problem the answer must be in reciprocal? Ex. 8/15 is written as 15/8 am correct.
Sudhansu said:
10 years ago
1-7/15 applied because the whole work is 1.
Mitsuna said:
10 years ago
"From the above answer, we can say 15/8 days required to.
Complete the remaining work by A and B".
Can you please calculate this in whole number so that we can assume the exact days remaining?
Complete the remaining work by A and B".
Can you please calculate this in whole number so that we can assume the exact days remaining?
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