Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
351 comments Page 16 of 36.

Indu said:   1 decade ago
Short trick if you are use to of percentage:

A's 1 day's work = 6.67% (100/15).
B's 1 day's work = 5%.

A+B's 1 day's work = 11.67%.
A+B's 4 day's work = 46.68%.

Remaining... 100-46.68 = 53.33% i.e. 8/15.

Vamshi said:   1 decade ago
@Deepa.

(1/15+1/20) L.C.M of 15, 20 is 60.

So 1/15*60 = 4.

And 1/20*60 = 3.

4+3/60 = 7/60.

Ashik said:   1 decade ago
Why have you taken 1 as total work? HOW?

Jansi said:   1 decade ago
I understood upto 7/15. I can't understand how they are telling total work 1. From that they were minusing 7/15 can you explain me.

Gurdeep said:   1 decade ago
@Jansi.

Both A and B doing the same (one) work, not different work.

Aravind said:   1 decade ago
We have to divide the denominator by its common divisible number and cross multiply it in numerator so you will get 7 then mutilply the highest remainder of lcm with the lowest denominator. You will get answer.

Thiyagu said:   1 decade ago
How the 0.53333 come 8/15 ?

Shrikant said:   1 decade ago
a/b + c/d.

= a*d/b*d + c*b/b*d.

= ad+cb/b*d.

Maths rule if denominator not equal if equal directly cross multiplication.

Shamanth Kumar Sm said:   1 decade ago
Can you explain how is 7/60 came?

Rajendra said:   1 decade ago
Good explanation but I can't understand how the 1- (7/15) is became 8/15.


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