Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
60 | 15 |
Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Discussion:
344 comments Page 13 of 35.
Esha said:
1 decade ago
How did 7/20 come?
Rashmi said:
1 decade ago
How did you get 7/60 please answer in simple method and tell how got 7.
Satish said:
1 decade ago
1/15+1/20= 7/60 How ? Please explain me clearly.
Pramesh said:
1 decade ago
@Rashmi, @Satish : 1/15 + 1/20 Now to make the denominator value equal take LCM i.e. ,
= (1*20) / (15*20) + (1*15) / (15*20) Now simplify these,
i.e. , multiply the values i.e. ,
= (20/300) + (15/300).
Now, both the denominator are equal, so you can add the numerator values i.e. , = (20+15) /300 = 35/300,
Now simplifying this i.e. , cancelling both numerator and denominator by 5 (a common value which both will get cancel) ,
We get 7/60. Hope this will help you to understand the problem.
= (1*20) / (15*20) + (1*15) / (15*20) Now simplify these,
i.e. , multiply the values i.e. ,
= (20/300) + (15/300).
Now, both the denominator are equal, so you can add the numerator values i.e. , = (20+15) /300 = 35/300,
Now simplifying this i.e. , cancelling both numerator and denominator by 5 (a common value which both will get cancel) ,
We get 7/60. Hope this will help you to understand the problem.
GUHAN said:
1 decade ago
@Swetha why mutiply with (A*TOTAL CAPACITY)?
Sanjana said:
1 decade ago
Thank you sundar nice explanation
Dipen said:
1 decade ago
How come Remaining work 1-7/15 (note:- why come 1 value )
Shiyamala said:
1 decade ago
A=1/15;B=1/20
[A+B]=[1/15+1/20] {1/15*20/20=20/300; 1/20*15/15=15/300}
=20+15/15*20 {cross multiplication}
=35/300 {20+15=35;15*20=300}
=7/60
7/60*4=28/60 {4*7=28}
=7/15
[A+B]=[1/15+1/20] {1/15*20/20=20/300; 1/20*15/15=15/300}
=20+15/15*20 {cross multiplication}
=35/300 {20+15=35;15*20=300}
=7/60
7/60*4=28/60 {4*7=28}
=7/15
Ashish said:
1 decade ago
@Esha.
It's not 7/20 its 7/60 and that came after addition of
Both work A and B
A+B= 1/15+1/20=20+15/15*20=35/300=7/60.
It's not 7/20 its 7/60 and that came after addition of
Both work A and B
A+B= 1/15+1/20=20+15/15*20=35/300=7/60.
Mittal said:
1 decade ago
Plzz solve this A and B can together finish a work in 30 days. They worked at it for 20 days and then B let.
The remaining work was done by A alone in 20 more days. B alone can do the entire work in.
(a) 48 days (b) 50 days (c) 54 days (d) 60 days.
The remaining work was done by A alone in 20 more days. B alone can do the entire work in.
(a) 48 days (b) 50 days (c) 54 days (d) 60 days.
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