Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 29)
29.
A and B can do a job together in 7 days. A is 1
times as efficient as B. The same job can be done by A alone in :
times as efficient as B. The same job can be done by A alone in :Answer: Option
Explanation:
| (A's 1 day's work) : (B's 1 day's work) = | 7 | : 1 = 7 : 4. |
| 4 |
Let A's and B's 1 day's work be 7x and 4x respectively.
| Then, 7x + 4x = | 1 |  11x = |
1 | x = |
1 | . |
| 7 | 7 | 77 |
 A's 1 day's work = |
 |
1 | x 7 |  |
= | 1 | . |
| 77 | 11 |
Discussion:
54 comments Page 5 of 6.
Heena said:
1 decade ago
@nidhi
if A=(7/4)B
then Eq2 should be
7/4(B)+B=1/7
if A=(7/4)B
then Eq2 should be
7/4(B)+B=1/7
Priya said:
1 decade ago
I didn't get why 7/4 is used?
Please explain.
Please explain.
Pawan narkhede said:
1 decade ago
How to come A is 7/4 times efficient than B?
Swapna said:
9 years ago
7+4=11......28 ,7....? 11/7*28 = 44 ans.
Bharathi said:
9 years ago
It's easy to understand. Thanks @Kuntal.
Girish said:
1 decade ago
Why we should multiply by 7 at the end ?
Varun said:
1 decade ago
Ratio type problem solve by 'x' value.
Hellani said:
9 years ago
Can you please explain me? Please.
(1)
Raj said:
1 decade ago
How we get A =7/4? Please help me.
Pankaj said:
2 decades ago
How Total Working Days=7*4=28 ?
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