Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 26)
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | ; |
| 6 |
| (A + B)'s 1 day's work = | 1 | ; |
| 8 |
| (B + C)'s 1 day's work = | 1 | . |
| 12 |
 (A + C)'s 1 day's work |
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So, A and C together will do the work in 8 days.
Discussion:
53 comments Page 5 of 6.
Nik said:
1 decade ago
1 day's work of(A+B)=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
Nice dreamer said:
1 decade ago
Why 2 is multiplied with 1/6 ? please explain any one.
Basu said:
1 decade ago
How its come on 1/6-1/2=1/12
1/6-1/8= 1/24
1/12+1/24= 1/8
1/6-1/8= 1/24
1/12+1/24= 1/8
Sujeet said:
1 decade ago
Why 2 is multiplied by 1/6.
Parveen verma said:
1 decade ago
(A+B+C)=1/6
A's one day work work= (A+B+C)-(B+C)= 1/6-1/12 =1/12
C's one day work work= (A+B+C)-(A+B)= 1/6-1/8= 1/24
(A+C)'s one day work= 1/12+1/24= 1/8
so the work will be completed in 8 days
A's one day work work= (A+B+C)-(B+C)= 1/6-1/12 =1/12
C's one day work work= (A+B+C)-(A+B)= 1/6-1/8= 1/24
(A+C)'s one day work= 1/12+1/24= 1/8
so the work will be completed in 8 days
Anishkumar said:
1 decade ago
Assume A+C as x
so now
2(A+B+C)=1/8+1/12+1/x
2(1/6) =5/24+1/x
finally
x =8
so now
2(A+B+C)=1/8+1/12+1/x
2(1/6) =5/24+1/x
finally
x =8
Kavitha said:
1 decade ago
Why did you take 1/6 (1/12+1/24) ?
Gulshan said:
1 decade ago
24 is lcm of 8 & 12
Sabarimani said:
1 decade ago
Is b's 1day work=1/6-(1/24+1/12)?
Azuu said:
1 decade ago
How to take lcm of 1/8+1/12 ?
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