Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
 C's 1 day's work = |
1 | - |  |
1 | + | 1 |  |
= | |
1 | - | 7 | |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
224 comments Page 8 of 23.
Bhavana said:
1 decade ago
Firstly take the LCM.
A B ABC.
16 12 4.
LCM IS 48 then ratio is.
A B ABC.
3 4 12.
If a+b-ABC then it's find the value of C = 5 total is 48.
Then divide the 48/5 so simple.
A B ABC.
16 12 4.
LCM IS 48 then ratio is.
A B ABC.
3 4 12.
If a+b-ABC then it's find the value of C = 5 total is 48.
Then divide the 48/5 so simple.
Dikesh said:
10 years ago
Hi all,
If we convert 5/48 can lead to decimal, normally we won't measure days of decimal, hence we have to reverse it simple that's it. I think all you guys understood this.
If we convert 5/48 can lead to decimal, normally we won't measure days of decimal, hence we have to reverse it simple that's it. I think all you guys understood this.
Anish said:
7 years ago
@Sunshine.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
Sunny said:
9 years ago
A's efficiency = 3, and B's efficiency =4, so (3 + 4) = 5 then C's efficiency (12 - 7) =5, So total work take LCM of (16, 12, 4) = 48, so C alone finished the work 48/5.
Shashi said:
6 years ago
A = 16.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
Amit.J said:
1 decade ago
A+B+C=4 day.
A=16 day.
B=12 day.
C=?
Formula..
A+B+C=A*B*C/AB+BC+CA
4=192C/192+28C
4(192+28C)=192C
768+112C=192C
768=192C-112C
768=80C
768/80=C
C=48/5 Ans.
A=16 day.
B=12 day.
C=?
Formula..
A+B+C=A*B*C/AB+BC+CA
4=192C/192+28C
4(192+28C)=192C
768+112C=192C
768=192C-112C
768=80C
768/80=C
C=48/5 Ans.
Ishita Jain said:
3 months ago
Can also be done like this;
(1/16) *4+ (1/12) * 4 + (1/x) * 4 = 1 (as the total work is 1).
Everybody together completes 1/4 of work in one day.
So, (1/4)*4 = 1.
(1/16) *4+ (1/12) * 4 + (1/x) * 4 = 1 (as the total work is 1).
Everybody together completes 1/4 of work in one day.
So, (1/4)*4 = 1.
(4)
Ajay jabalpur said:
1 decade ago
@Hiren.
If A's one day work = 1/n, then A can finish the work in n/1 days.
Similarly,
C's one day work is 5/48, then C can finish the work in 48/5 days.
If A's one day work = 1/n, then A can finish the work in n/1 days.
Similarly,
C's one day work is 5/48, then C can finish the work in 48/5 days.
Vinay said:
8 years ago
A = 1/16.
B = 1/12.
According to Qsn A + B + C = 1/4.
Add A, B values.
Here,
1/16 + 1/12 + C = 1/4,
C = 1/4 - 1/16 - 1/12,
= 5/48.
Total Days of C = 48/5.
B = 1/12.
According to Qsn A + B + C = 1/4.
Add A, B values.
Here,
1/16 + 1/12 + C = 1/4,
C = 1/4 - 1/16 - 1/12,
= 5/48.
Total Days of C = 48/5.
Rickykerketta said:
3 years ago
A --- 15.
B --- 20.
We took LCM -- 60.
15 * 4 = 60.
20 * 3 = 60.
Work done = 4 days * 7 = 28 units of work.
60 - 28 = 32,
Part left = 32/60,
8/32.
B --- 20.
We took LCM -- 60.
15 * 4 = 60.
20 * 3 = 60.
Work done = 4 days * 7 = 28 units of work.
60 - 28 = 32,
Part left = 32/60,
8/32.
(5)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers