Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
 C's 1 day's work = |
1 | - |  |
1 | + | 1 |  |
= | |
1 | - | 7 | |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
226 comments Page 8 of 23.
Gunjan said:
4 years ago
Agree @Truptimayee Bahinipati.
A=15 days.
B= 20 days.
Then the addition of 1/15 + 1/20 =7/60.
7/60 x 4 = 28/60, 28/60 = 14/30, 14/30 = 7/15.
[ 1- 7/15 ] = 8/15.
Answer = 8/15.
A=15 days.
B= 20 days.
Then the addition of 1/15 + 1/20 =7/60.
7/60 x 4 = 28/60, 28/60 = 14/30, 14/30 = 7/15.
[ 1- 7/15 ] = 8/15.
Answer = 8/15.
Sagar said:
1 decade ago
@SHALU
SUPPOSE A,B,C ARE HAVING 10 RUPIEES
WE KNOW DAT A=5 AND B=3 NW WE HAVE TO FIND C
THEN WE WILL ADD BOTH A AND B AND REMOVE FRM TOTAL HERE ALSO SAME WE HAD DONE
UNDERSTOOD
SUPPOSE A,B,C ARE HAVING 10 RUPIEES
WE KNOW DAT A=5 AND B=3 NW WE HAVE TO FIND C
THEN WE WILL ADD BOTH A AND B AND REMOVE FRM TOTAL HERE ALSO SAME WE HAD DONE
UNDERSTOOD
Bhavana said:
1 decade ago
Firstly take the LCM.
A B ABC.
16 12 4.
LCM IS 48 then ratio is.
A B ABC.
3 4 12.
If a+b-ABC then it's find the value of C = 5 total is 48.
Then divide the 48/5 so simple.
A B ABC.
16 12 4.
LCM IS 48 then ratio is.
A B ABC.
3 4 12.
If a+b-ABC then it's find the value of C = 5 total is 48.
Then divide the 48/5 so simple.
Dikesh said:
10 years ago
Hi all,
If we convert 5/48 can lead to decimal, normally we won't measure days of decimal, hence we have to reverse it simple that's it. I think all you guys understood this.
If we convert 5/48 can lead to decimal, normally we won't measure days of decimal, hence we have to reverse it simple that's it. I think all you guys understood this.
Anish said:
7 years ago
@Sunshine.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
Sunny said:
9 years ago
A's efficiency = 3, and B's efficiency =4, so (3 + 4) = 5 then C's efficiency (12 - 7) =5, So total work take LCM of (16, 12, 4) = 48, so C alone finished the work 48/5.
Shashi said:
7 years ago
A = 16.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
Amit.J said:
1 decade ago
A+B+C=4 day.
A=16 day.
B=12 day.
C=?
Formula..
A+B+C=A*B*C/AB+BC+CA
4=192C/192+28C
4(192+28C)=192C
768+112C=192C
768=192C-112C
768=80C
768/80=C
C=48/5 Ans.
A=16 day.
B=12 day.
C=?
Formula..
A+B+C=A*B*C/AB+BC+CA
4=192C/192+28C
4(192+28C)=192C
768+112C=192C
768=192C-112C
768=80C
768/80=C
C=48/5 Ans.
Ishita Jain said:
6 months ago
Can also be done like this;
(1/16) *4+ (1/12) * 4 + (1/x) * 4 = 1 (as the total work is 1).
Everybody together completes 1/4 of work in one day.
So, (1/4)*4 = 1.
(1/16) *4+ (1/12) * 4 + (1/x) * 4 = 1 (as the total work is 1).
Everybody together completes 1/4 of work in one day.
So, (1/4)*4 = 1.
(10)
Ajay jabalpur said:
1 decade ago
@Hiren.
If A's one day work = 1/n, then A can finish the work in n/1 days.
Similarly,
C's one day work is 5/48, then C can finish the work in 48/5 days.
If A's one day work = 1/n, then A can finish the work in n/1 days.
Similarly,
C's one day work is 5/48, then C can finish the work in 48/5 days.
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