Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
C's 1 day's work = |
1 | - | ![]() |
1 | + | 1 | ![]() |
= | ![]() |
1 | - | 7 | ![]() |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
228 comments Page 20 of 23.
Amrut said:
1 decade ago
C s one day work is 5/48. But how you came to 48/5, I mean C finish job in 48/5 days. Is there any formula for this result?
Udita said:
1 decade ago
@Saquib Ali.
Please explain the following step.
Units of work in a day by a = 48x/16 = 48 units.
Please explain the following step.
Units of work in a day by a = 48x/16 = 48 units.
Tiny said:
1 decade ago
@chandrakant.
Your method is totaly wrong. When c comes in right hand side it will become negative.
Your method is totaly wrong. When c comes in right hand side it will become negative.
Indian said:
1 decade ago
@ Ovii
Thanks for explanation, Now I understood well.
Thanks for explanation, Now I understood well.
Chandrakant said:
1 decade ago
Wan we do it this way?
A=16days B=12days, and A+B+C=4 days
So 16+12+C = 4
i.e; 28-4 = c
Hence c = 24days
NOTE: Pls tell me if this method is correct, if not then why?
A=16days B=12days, and A+B+C=4 days
So 16+12+C = 4
i.e; 28-4 = c
Hence c = 24days
NOTE: Pls tell me if this method is correct, if not then why?
Swetha said:
1 decade ago
1/12+1/16
=4+3/48
=7/48
=4+3/48
=7/48
VASUDEVARAO said:
1 decade ago
Thank you nikitha well s. C method thanku.
Simran said:
1 decade ago
Thanks for the help.
Ovii said:
1 decade ago
@aparna
Little help to the explanation of 1's days work.
If A's 1 day work = 1/n than the complete/whole work can be done in n*1 days.
It can be modify to above 1 day's work, e.g
if A's 5 days work = 1/25, than the complete/whole work = 5*25= 125.
Little help to the explanation of 1's days work.
If A's 1 day work = 1/n than the complete/whole work can be done in n*1 days.
It can be modify to above 1 day's work, e.g
if A's 5 days work = 1/25, than the complete/whole work = 5*25= 125.
Meenakshi dhawan said:
1 decade ago
@Saquib Ali.
You have solved it wisely.
You have solved it wisely.
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C's 1 day's work =
