Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
 C's 1 day's work = |
1 | - |  |
1 | + | 1 |  |
= | |
1 | - | 7 | |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
224 comments Page 2 of 23.
Siba siddquie said:
7 years ago
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
LCm of A,B,A+B+C (16,12,4)=total work=48...;;
A' 1 day work=48/16=3;
same B=48/12=4..A+B+C=48/4=12,
A+B+C=12,
3+4+C=12,
C 'one day work =5,
total work is =48.
C completes the work in (days) = total work/one day work..(formula) = 48/5=9(3/5) => answer.
LCm of A,B,A+B+C (16,12,4)=total work=48...;;
A' 1 day work=48/16=3;
same B=48/12=4..A+B+C=48/4=12,
A+B+C=12,
3+4+C=12,
C 'one day work =5,
total work is =48.
C completes the work in (days) = total work/one day work..(formula) = 48/5=9(3/5) => answer.
Anurag Singh said:
8 years ago
A work = 16 days.
B work = 12 days.
Total work done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done bye C in one day= 20/4 = 5 unit.
So total work done by C in days = 48/5 days =9*3/5 days.
B work = 12 days.
Total work done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done bye C in one day= 20/4 = 5 unit.
So total work done by C in days = 48/5 days =9*3/5 days.
Asshok007 said:
9 years ago
@Shantanu
Thank you, you are right.
Actually, A can solve in 16 days for one day it will be 1/16. if we take for 2 days work it will become 2/16. in the same way the work done by c per day is 5/48. If you want total work done by 'c' just reverse the fraction like 48/5.
Ex: THE TOTAL WORK DONE BY 'B' IS IN 12DAYS, FOR ONE DAY 12,IN THE SCENE 12/1. You should remember that 5/48 is the work done by 'c' in one day.
Thank you, you are right.
Actually, A can solve in 16 days for one day it will be 1/16. if we take for 2 days work it will become 2/16. in the same way the work done by c per day is 5/48. If you want total work done by 'c' just reverse the fraction like 48/5.
Ex: THE TOTAL WORK DONE BY 'B' IS IN 12DAYS, FOR ONE DAY 12,IN THE SCENE 12/1. You should remember that 5/48 is the work done by 'c' in one day.
Suryakiran varma said:
1 decade ago
Look,
A can do a work in 16 days,so his one day work will be=1/16
and also B's one day work will be =1/12;
in the same way A,B,C together do a work in 4 days,so thier one day work will be=1/4
C 's one day work will be=(A+B+C)'s one day work - (A+B)'s one day work
i.e..
=(1/4)-(1/16+1/12)
=(1/4)-(7/48)
=(5/48)
thus,C's one day work is = 5/48,
so,he can do the work in 48/5 days..i.e..9 3/5.
A can do a work in 16 days,so his one day work will be=1/16
and also B's one day work will be =1/12;
in the same way A,B,C together do a work in 4 days,so thier one day work will be=1/4
C 's one day work will be=(A+B+C)'s one day work - (A+B)'s one day work
i.e..
=(1/4)-(1/16+1/12)
=(1/4)-(7/48)
=(5/48)
thus,C's one day work is = 5/48,
so,he can do the work in 48/5 days..i.e..9 3/5.
Shivani said:
7 years ago
A can do the work = 16 days,
B can do the work =12days,
A+B+C together can do work =4 days.
let's take the LCM of 16,12 and 4 it is 48.
calculate the 1 day's work of A,B and A+B+C,
1day's work of A= 48/16= 3,
1day's work of B= 48/12= 4,
1day's work of A+B+C =48/4=12,
Here we calculate the 1day's work of c,
A+B+C=12,
3+4+C=12,
7+C=12,
C=12-7,
C=5.
Then,
c alone can do the work in;
C = 48/5 = 9 * 3/5 days.
B can do the work =12days,
A+B+C together can do work =4 days.
let's take the LCM of 16,12 and 4 it is 48.
calculate the 1 day's work of A,B and A+B+C,
1day's work of A= 48/16= 3,
1day's work of B= 48/12= 4,
1day's work of A+B+C =48/4=12,
Here we calculate the 1day's work of c,
A+B+C=12,
3+4+C=12,
7+C=12,
C=12-7,
C=5.
Then,
c alone can do the work in;
C = 48/5 = 9 * 3/5 days.
Ganesh said:
10 years ago
Total work is 48 units.
A can do work in 16 days.
It means A completes 3 units per day.
B can do work in 12 days.
It means B completes 4 units per day.
Now A and B is helped by C and completed work in 4 days.
It means A, B and C together doing 12 units per day.
It means A+B+C = 12.
Sub A and B values.
3+4+C = 12.
C = 5.
It means C completes 5 units per day.
For 48 units?
Answer: 48/5.
A can do work in 16 days.
It means A completes 3 units per day.
B can do work in 12 days.
It means B completes 4 units per day.
Now A and B is helped by C and completed work in 4 days.
It means A, B and C together doing 12 units per day.
It means A+B+C = 12.
Sub A and B values.
3+4+C = 12.
C = 5.
It means C completes 5 units per day.
For 48 units?
Answer: 48/5.
(1)
Adusumalli prasanna said:
1 decade ago
a+b+c=1/4 a's 1st day work = 1/16 b's 1st day work = 1/12.
Therefore c's 1 day work = 1/4-{1/16+1/12) after that 1/4-(12+16/192) {by doing LCM) by dividing 28/192 (by multiplying 2nd table) then we get 1/4-7/48 (by doing LCM).
We get (48-28/192) = 20/192 = 10/96 (dividing with 2 table) we get 5/48. Now please help me why we are taking as 48/5.
Whats the reason explain me clearly please?
Therefore c's 1 day work = 1/4-{1/16+1/12) after that 1/4-(12+16/192) {by doing LCM) by dividing 28/192 (by multiplying 2nd table) then we get 1/4-7/48 (by doing LCM).
We get (48-28/192) = 20/192 = 10/96 (dividing with 2 table) we get 5/48. Now please help me why we are taking as 48/5.
Whats the reason explain me clearly please?
Jamshed Alam said:
8 years ago
A = 16 Days.
B = 12 Days.
A+B+C = 4 Days.
C = ?
1st of all we take LCM of 16, 12, and 4.
LCM of 16,12 and 4 is 48.
It means whole work is 48 unit then we find the unit of per day of all.
A = 48/16 = 3unit/day.
B = 48/12 = 4unit/day.
A+B+C = 48/4 = 12unit/day.
A+B = 3+4 = 7unit/day.
Now subtract from (A+B+C)-(A+B)=12-7 = 5.
C = 5unit/day.
It means C can alone of whole work is 48/5 days.
B = 12 Days.
A+B+C = 4 Days.
C = ?
1st of all we take LCM of 16, 12, and 4.
LCM of 16,12 and 4 is 48.
It means whole work is 48 unit then we find the unit of per day of all.
A = 48/16 = 3unit/day.
B = 48/12 = 4unit/day.
A+B+C = 48/4 = 12unit/day.
A+B = 3+4 = 7unit/day.
Now subtract from (A+B+C)-(A+B)=12-7 = 5.
C = 5unit/day.
It means C can alone of whole work is 48/5 days.
Dibyanshu said:
3 years ago
The work is completed by A in 16 days and by B in 12.
LCM of 16 and 12 is 48.(Total work is also 48).
The efficiency of A= 48/16=3 and B= 48/12=4,
They complete the work in 4 days.
Total work/time = Efficiency.
48/4 = 12(Efficiency of A+B+C = 12).
The efficiency of A+B is 3+4=7
The efficiency of C is 12 - 7 = 5.
Total work/Efficiency = Time.
48/5 = 9.6 is also written as (9*3/5).
LCM of 16 and 12 is 48.(Total work is also 48).
The efficiency of A= 48/16=3 and B= 48/12=4,
They complete the work in 4 days.
Total work/time = Efficiency.
48/4 = 12(Efficiency of A+B+C = 12).
The efficiency of A+B is 3+4=7
The efficiency of C is 12 - 7 = 5.
Total work/Efficiency = Time.
48/5 = 9.6 is also written as (9*3/5).
(10)
Srinivas said:
1 decade ago
If I go for another way as follows:
A B and C can do work in 4days.
A alone 16 days.
B alone 12 days.
C alone ?... Lets assume it as X.
Let me apply this formula
Work done by A B and C put together i.e 4= (16*12*X)/(16+12+X) //(A*B*C)/(A+B+C).
28+X=48X.
28=47X.
X=28/47.
According To you Answer is Wrong How is it. Please Reply me As soon As possible.
A B and C can do work in 4days.
A alone 16 days.
B alone 12 days.
C alone ?... Lets assume it as X.
Let me apply this formula
Work done by A B and C put together i.e 4= (16*12*X)/(16+12+X) //(A*B*C)/(A+B+C).
28+X=48X.
28=47X.
X=28/47.
According To you Answer is Wrong How is it. Please Reply me As soon As possible.
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