Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 12)
12.
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
| Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
| 8 | 10 |
| Solving the two equations, we get: x = | 11 | , y = | 1 |
| 400 | 400 |
 1 woman's 1 day's work = |
1 | . |
| 400 |
 10 women's 1 day's work = |
 |
1 | x 10 |  |
= | 1 | . |
| 400 | 40 |
Hence, 10 women will complete the work in 40 days.
Discussion:
106 comments Page 8 of 11.
Jayalakshmi said:
1 decade ago
Can you please explain.
How comes.
4x + 6y = 1/8 and 3x + 7y = 1/10.
X = 11/400, y = 1/400.
In easy method above mentioned methods are very difficult to understand.
How comes.
4x + 6y = 1/8 and 3x + 7y = 1/10.
X = 11/400, y = 1/400.
In easy method above mentioned methods are very difficult to understand.
Afia Sharmin said:
1 decade ago
Answer for: 6 men and 8 women can do a work in 18 days. How many days will it require to complete the whole work if 3 men and 5 women work together?
Ami said:
1 decade ago
4x+6y=1/8 ----(1)
3x+7y=1/10 ----(2)
now,multiply equation 1 with 3 and equ.2 with 4
12x+18y=3/8
12x+28y=2/5
- - -
-------------
-10y=-1/40
10y=1/40 so, 40 become ans
3x+7y=1/10 ----(2)
now,multiply equation 1 with 3 and equ.2 with 4
12x+18y=3/8
12x+28y=2/5
- - -
-------------
-10y=-1/40
10y=1/40 so, 40 become ans
Srinivas said:
1 decade ago
4x+6y=1/8.
3x+7y=1/10.
Here why you are taking days 1/10 and 1/8?
You mean members=1/days ?
3x+7y=1/10.
Here why you are taking days 1/10 and 1/8?
You mean members=1/days ?
MOHAMED SALEEM said:
1 decade ago
Let us sahre CHAN HOW 1 BECOMES 30/8
32x + 48y = 1 --(1) ----> (1) * 30
960x+1440y=30/8 (since 30*32 =960)
32x + 48y = 1 --(1) ----> (1) * 30
960x+1440y=30/8 (since 30*32 =960)
Adithi said:
1 decade ago
4 men + 6 Women completes 1/8 of the work
i.e., 4m + 6w = 1/8 --- equation I
3 men + 7women completes 1/10 of the work
i.e ., 3m + 7w = 1/10 --- equation II
Multiply Equation I*3 and Equation II * 4 we get
12m + 18w =3/8
12m + 28w =4/10 ( now subtract)
------------------------------
0 + 10 w = 3/8 -4/10 = 1/40
------------------------------
hence 10 women takes 40 days !
i.e., 4m + 6w = 1/8 --- equation I
3 men + 7women completes 1/10 of the work
i.e ., 3m + 7w = 1/10 --- equation II
Multiply Equation I*3 and Equation II * 4 we get
12m + 18w =3/8
12m + 28w =4/10 ( now subtract)
------------------------------
0 + 10 w = 3/8 -4/10 = 1/40
------------------------------
hence 10 women takes 40 days !
Katam brahmareddy said:
1 decade ago
4x + 6y =1/8*3 and 3x + 7y =1/10*4
12x+18y=3/8 and 12x+28y=2/5
subtract them
12x+18y-3/8-12x-28y+2/5=0
ofter
-10y=-3/8+2/5
=-15+16/40
=1/40 (it is work done for day with ten womens)
-10y=1/40*10
=1/40
answer is 40 days..
12x+18y=3/8 and 12x+28y=2/5
subtract them
12x+18y-3/8-12x-28y+2/5=0
ofter
-10y=-3/8+2/5
=-15+16/40
=1/40 (it is work done for day with ten womens)
-10y=1/40*10
=1/40
answer is 40 days..
Prasant said:
1 decade ago
4x+6y = 1/8
=> 4x+6/400 = 1/8 ...as x=1/400
=> 4x = 1/8-6/400
=> 4x = 11/100
=> x = 11/400
=> 4x+6/400 = 1/8 ...as x=1/400
=> 4x = 1/8-6/400
=> 4x = 11/100
=> x = 11/400
Kalyan said:
1 decade ago
Hi can any body say how 11/400 is possible?
Nira said:
1 decade ago
How we get 8*50w=10w?
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