Aptitude - Time and Work - Discussion

How can this problem be solved if the supporting statement isn't given, that is "3 men and 7 women complete work in 10 days. ".

What if the question is "4 men and 6 women can complete the work in 8 days then how many days it will take for 10 women to finish the work?".

6/400 = 3/200.

Take LCM of 1/8-3/200 = 440/4000 = 11/100.
Is it clear?

Hi, can anybody explain how comes 1/8-6/400 =11/100?

I have a best answer:
4M + 6W = 8 days.

32M + 48W = 1 day --- 1.
3M + 7W = 10 days.

30M + 70W = 1 day ----2.
From 1 and 2, we get.

2M = 22W.
1M = 11W.

and also 3M = 33W.

Subs in 3M + 7W = 10 days.
we get, 33W + 7W = 10 days.

40W = 10 days.

Then,
10W = 40 days.

Ok I didn't see all the example but I tried and found the following the easiest.

Men= x, Women= y.
So
(4x + 6y) will all the work in ? ans= 8 days (Given).

Then work done by (4x+6y) in 1 day = 1/8 (eq 1) simple, right ?).

Similarly we will get 3x+7y = 1/10... (eq 2).

Now if we can find out the amount of work done by 1 women (i.e - Y) then we can easily find out work done by 10 ?

2 eq

4x + 6 y = 1/8

3x + 7y = 1/10 Now think if we can eliminate X from the eq

Hmm.. Multiply eq 1 by 3 i.e 3* (4x + 6y = 1/8)

Multiply eq 2 by 4 i.e 4* (3x + 7y = 1/10)

We will get?

12x + 18y = 3/8.

12x + 28y = 4/10 or 12x + 28 y = 2/5 .

subtract them . X is gone :D

28y-18y = 2/5 - 3/8

=> 10y= 16-15/40

=> 10y= 1/40

=> y = 1/400 ( This is all we wanted ) .

1 women (i.e y ) can do 1/400 of work.

10 women will do in ? 10*1/400 = 1/40.

Actually 40 days! done.

Hi I can't understand this problem.

Can we solve like this way.

4 man and 6 women = 8 days.

3 man and 7 women = 10 days.

So,

2 man and 8 women = 12 days.

1 man and 9 women = 14 days.

0 man and 10 women = 16 days.

Is it right way.

Hi guys, Kindly solve those two equation in step by step with simple format.

One day work by 4M + 6W = 1\8 --- (1).
One day work by 3M + 7W = 1\10 --- (2).

10W = ?

Multiply (1) by 3 and (2) by 4

12M + 18W = 3/8 => 12M = 3/8 - 18W --- (3).
12M + 28W = 4/10 => 12M + 28W = 2/5 --- (4).

Putting 12M value from (3) to (4)

3/18 - 18W + 28W = 2/5.
10W = 2/5 - 3/8.
10W = 1/40.

Since one day work by 10W = 1/40.

Hence, 10 women will complete the work in 40 days.

If 4M+6w = 1/8 ---- (1)x 3.
3M+7w = 1/10 ----(2)x 4.

And

12M+18W = 3/18.
12M+28w = 4/10.

Than

10W = 2/5 - 3/8 = 1/40.
Answer 10 W = 40, Option (B).

4M+6W=8 ----1
3M+7W=10 ----2
10W = ? ----3

8*4M+8*6w = 10*3M+10*7W
32M+48W = 30M+70W
32M-30M = 70W-48W
2M = 22W
1M = 11W

PUT IN EQ-2.

33W+7W = 10
40W = 10

40*10= 10*?
?= 40.