Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 12)
12.
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
35
40
45
50
Answer: Option
Explanation:

Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.

Then, 4x + 6y = 1 and 3x + 7y = 1 .
8 10

Solving the two equations, we get: x = 11 , y = 1
400 400

1 woman's 1 day's work = 1 .
400

10 women's 1 day's work = 1 x 10 = 1 .
400 40

Hence, 10 women will complete the work in 40 days.

Discussion:
106 comments Page 4 of 11.

Adithi said:   1 decade ago
4 men + 6 Women completes 1/8 of the work
i.e., 4m + 6w = 1/8 --- equation I

3 men + 7women completes 1/10 of the work
i.e ., 3m + 7w = 1/10 --- equation II

Multiply Equation I*3 and Equation II * 4 we get
12m + 18w =3/8
12m + 28w =4/10 ( now subtract)
------------------------------
0 + 10 w = 3/8 -4/10 = 1/40
------------------------------
hence 10 women takes 40 days !

MOHAMED SALEEM said:   1 decade ago
Let us sahre CHAN HOW 1 BECOMES 30/8

32x + 48y = 1 --(1) ----> (1) * 30
960x+1440y=30/8 (since 30*32 =960)

Srinivas said:   1 decade ago
4x+6y=1/8.

3x+7y=1/10.

Here why you are taking days 1/10 and 1/8?

You mean members=1/days ?

Ami said:   1 decade ago
4x+6y=1/8 ----(1)
3x+7y=1/10 ----(2)
now,multiply equation 1 with 3 and equ.2 with 4

12x+18y=3/8
12x+28y=2/5
- - -
-------------
-10y=-1/40
10y=1/40 so, 40 become ans

Afia Sharmin said:   1 decade ago
Answer for: 6 men and 8 women can do a work in 18 days. How many days will it require to complete the whole work if 3 men and 5 women work together?

Jayalakshmi said:   1 decade ago
Can you please explain.

How comes.

4x + 6y = 1/8 and 3x + 7y = 1/10.

X = 11/400, y = 1/400.

In easy method above mentioned methods are very difficult to understand.

Syed said:   1 decade ago
4M+6W=8 ----1
3M+7W=10 ----2
10W = ? ----3

8*4M+8*6w = 10*3M+10*7W
32M+48W = 30M+70W
32M-30M = 70W-48W
2M = 22W
1M = 11W

PUT IN EQ-2.

33W+7W = 10
40W = 10

40*10= 10*?
?= 40.

Vinod Anand said:   1 decade ago
If 4M+6w = 1/8 ---- (1)x 3.
3M+7w = 1/10 ----(2)x 4.

And

12M+18W = 3/18.
12M+28w = 4/10.

Than

10W = 2/5 - 3/8 = 1/40.
Answer 10 W = 40, Option (B).

Adnan said:   1 decade ago
One day work by 4M + 6W = 1\8 --- (1).
One day work by 3M + 7W = 1\10 --- (2).

10W = ?

Multiply (1) by 3 and (2) by 4

12M + 18W = 3/8 => 12M = 3/8 - 18W --- (3).
12M + 28W = 4/10 => 12M + 28W = 2/5 --- (4).

Putting 12M value from (3) to (4)

3/18 - 18W + 28W = 2/5.
10W = 2/5 - 3/8.
10W = 1/40.

Since one day work by 10W = 1/40.

Hence, 10 women will complete the work in 40 days.

Suresh said:   1 decade ago
Hi guys, Kindly solve those two equation in step by step with simple format.


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