Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 12)
12.
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
8 | 10 |
Solving the two equations, we get: x = | 11 | , y = | 1 |
400 | 400 |
![]() |
1 | . |
400 |
![]() |
![]() |
1 | x 10 | ![]() |
= | 1 | . |
400 | 40 |
Hence, 10 women will complete the work in 40 days.
Discussion:
106 comments Page 11 of 11.
Karthikeyan said:
4 years ago
4x+6y=1/8 ------> (1)
3x+7y=1/10 ----> (2).
Eqn 1 divided by 3.
Eqn 2 divided by 4.
12x+18y=3/8----(3).
12x+28y=4/10---(4).
-------------------------
-10y=1/40.
Y=1/40*10.
y=1/400.
Y value substitute in eqn (1).
4x+6(1/400) =1/8,
4x+6/400=1/8,
4x=1/8-6/400,
4x=44/400,
X=44/400*4,
X=11/400.
1 women complete a work=1/400*10.
1/40.
Hence, 10 women
3x+7y=1/10 ----> (2).
Eqn 1 divided by 3.
Eqn 2 divided by 4.
12x+18y=3/8----(3).
12x+28y=4/10---(4).
-------------------------
-10y=1/40.
Y=1/40*10.
y=1/400.
Y value substitute in eqn (1).
4x+6(1/400) =1/8,
4x+6/400=1/8,
4x=1/8-6/400,
4x=44/400,
X=44/400*4,
X=11/400.
1 women complete a work=1/400*10.
1/40.
Hence, 10 women
(11)
Hemaharshini T said:
2 years ago
4m + 6w = 8 days.
3m + 7w = 10 days.
10w = Tdays.
4m + 6w = 1/8days --->(1)
3m + 7w = 1/10days ----> (2)
10w = Tdays ----> (3)
1st step is to find the value of m and w with (1)&(2)
32m + 48w = 30m + 70w.
32m - 30m = 70w - 48w.
m/w = 22/2.
m = 11 w = 1.
By product method;
(2)=(3).. you can also take (1) instead of (2).
mw*T = mw*T.
[3(11) + 7(1)] * 10 = 10 * T.
400 = 10T.
T = 40days.
3m + 7w = 10 days.
10w = Tdays.
4m + 6w = 1/8days --->(1)
3m + 7w = 1/10days ----> (2)
10w = Tdays ----> (3)
1st step is to find the value of m and w with (1)&(2)
32m + 48w = 30m + 70w.
32m - 30m = 70w - 48w.
m/w = 22/2.
m = 11 w = 1.
By product method;
(2)=(3).. you can also take (1) instead of (2).
mw*T = mw*T.
[3(11) + 7(1)] * 10 = 10 * T.
400 = 10T.
T = 40days.
(12)
Likitha Ganta said:
2 years ago
Given:
4m + 6w = 8 days ---> (1)
3m + 7w = 10 days ---> (2)
Total work = Efficiency × days.
By solving equation (1) and (2).
(4m + 6w) × 8 = (3m + 7w) × 10.
16m + 24w = 15m + 35w,
16m - 15m = 35w - 24w,
m = 11w.
Total work = (4 × 11 + 6) × 8.
Total work = 400 unit.
Time taken by 10 women = 400/10.
Time taken by 10 women = 40 days.
4m + 6w = 8 days ---> (1)
3m + 7w = 10 days ---> (2)
Total work = Efficiency × days.
By solving equation (1) and (2).
(4m + 6w) × 8 = (3m + 7w) × 10.
16m + 24w = 15m + 35w,
16m - 15m = 35w - 24w,
m = 11w.
Total work = (4 × 11 + 6) × 8.
Total work = 400 unit.
Time taken by 10 women = 400/10.
Time taken by 10 women = 40 days.
(17)
Urvashi said:
1 year ago
4m+6w=8 days.
3m+7w=10 days.
10w=?
(4m+6w)=1/8.
(3m+7w)=1/10.
Now,
32m + 48w = 30m + 70w.
2m = 22w
2/22 * m = Bawa
2/22 = w/m.
so, w=2 and m=22,
again,
(4m+6w)*8=(10w)*x.
(4*22+6*2)*8=(10*2)*x.
800=20x.
x=40 answer.
3m+7w=10 days.
10w=?
(4m+6w)=1/8.
(3m+7w)=1/10.
Now,
32m + 48w = 30m + 70w.
2m = 22w
2/22 * m = Bawa
2/22 = w/m.
so, w=2 and m=22,
again,
(4m+6w)*8=(10w)*x.
(4*22+6*2)*8=(10*2)*x.
800=20x.
x=40 answer.
(7)
Vijay said:
1 year ago
4m + 6w = 1/8 -------------------(1)
3m + 7w = 1/10 ------------------(2)
Then (1) *3 & (2)*4.
12m + 18w = 3/8 -------->(3)
12m + 28w = 4/10 ------> (4)
(4)-(3).
You will get 10w=1/40
Therefore, 40 days is the answer.
3m + 7w = 1/10 ------------------(2)
Then (1) *3 & (2)*4.
12m + 18w = 3/8 -------->(3)
12m + 28w = 4/10 ------> (4)
(4)-(3).
You will get 10w=1/40
Therefore, 40 days is the answer.
(57)
Utkarsh said:
7 months ago
@All
Make an equation;
4m + 6w = 8d ---> 1
3m + 7w = 10d ---> 2
Step 2:
Eliminate or make RHS of both the Eqn equal ie:days
32m + 48w = 1d (divide RHS by 8 and multiply LHS by 8)
30m + 70w = 1d (same)
Step3: RHS = LHS( find the relationship of efficient b/w men and women)
32m + 48w = 30m + 70w
2m = 22w
1m = 11w.
Step4: put it in any eqn 1.
44w + 6w = 8d.
50w = 8d.
400w = 1d ..ie to finish the work in 1 day 400 women are needed.
Now to finish the work in 10 days,
400w = x * 10d (x is the amount of work),
x = 400/10 = 40 days.
Make an equation;
4m + 6w = 8d ---> 1
3m + 7w = 10d ---> 2
Step 2:
Eliminate or make RHS of both the Eqn equal ie:days
32m + 48w = 1d (divide RHS by 8 and multiply LHS by 8)
30m + 70w = 1d (same)
Step3: RHS = LHS( find the relationship of efficient b/w men and women)
32m + 48w = 30m + 70w
2m = 22w
1m = 11w.
Step4: put it in any eqn 1.
44w + 6w = 8d.
50w = 8d.
400w = 1d ..ie to finish the work in 1 day 400 women are needed.
Now to finish the work in 10 days,
400w = x * 10d (x is the amount of work),
x = 400/10 = 40 days.
(3)
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