Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 35 of 36.
Samathu said:
1 decade ago
Nice explanation baskar.
Naari said:
1 decade ago
@vikas.
Good work dude.
Good work dude.
Sudhansu sekhar said:
10 years ago
Why applied 1/10 + 1/10?
Dipankar said:
7 years ago
12-60.
1-5,
So 3=5*3=15.
1-5,
So 3=5*3=15.
Divya said:
1 decade ago
Why we taken 1/10+1/10?
Arun said:
1 decade ago
How to make first step?
Divya said:
1 decade ago
Chitra its very clear.
Himanshu said:
6 years ago
How it is 3*5 at last?
Suneel kumar said:
1 decade ago
Why you multiply 3*5?
Narendra patidar said:
1 decade ago
Please clear explain.
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