Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
359 comments Page 19 of 36.
Manju said:
1 decade ago
LCM OF 20, 30, 60 is 60. Work out LCM method that means 10*2*3=60.
Tarun said:
1 decade ago
Anyone explain this question with LCM method.
Jibinlal said:
1 decade ago
1/5 work is done in 3 days. Remaining work is 4/5.
1/5+1/5+1/5+1/5 = 3+3+3+3 = 12 days.
Total = 12 days (4/5th work)+3 days (1/5th work). So 15 days.
1/5+1/5+1/5+1/5 = 3+3+3+3 = 12 days.
Total = 12 days (4/5th work)+3 days (1/5th work). So 15 days.
Manju verma said:
1 decade ago
Thank you for the solution its really easy way to understand.
Mareeswari said:
1 decade ago
Sir I can't understand the A is working two days please explain.
Lakhan said:
1 decade ago
Why 3 is multiplied by 5 in first method?
Manisha said:
1 decade ago
Please tell me answer in LCM method.
Narendra patidar said:
1 decade ago
Please clear explain.
Varun said:
1 decade ago
How you can take total working days as 3 in last step?
Satish kumar said:
1 decade ago
How will make step 3 (1/10+1/10) explain?
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