Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
30 days
40 days
60 days
70 days
Answer: Option
Explanation:

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1 and 16x + 44y = 1.
30

Solving these two equations, we get: x = 1 and y = 1
60 60

B's 1 day's work = 1 .
60

Hence, B alone shall finish the whole work in 60 days.

Discussion:
97 comments Page 9 of 10.

Priyanka said:   1 decade ago
@vidya :- we are taking 1/30 , becoz we are talking about work completed by x and y in one day .

Pandit said:   1 decade ago
@Kanna.

You explain very easly. Thanks a lot.

Thangeswari said:   1 decade ago
Kanna.

Thanks a lot. Your explanation was excellent.

Soniya said:   1 decade ago
@kanna.

You are right. Thanks.

SHEIK said:   1 decade ago
@Kanna

Your explanation is good and easily understandable.

Yogi said:   1 decade ago
@Manasa

Yes you are corrrect.

Vidhya said:   1 decade ago
What is the need to write number of days as a ratio?

Why cant we take it as x+y=30 ?

Manasa said:   1 decade ago
A's 1 day work ,consider X
B's 1 day work ,consider Y
(A+B) 1 day work=(X+Y)=1/30
next condition:
A works for 16 days=16*X
B works for 44 days for remaining work to complete=44*Y
to complete whole work;16X+44Y=1
by solving both equations ,we get
X=1/60,Y=1/60
B can complete work in 60 days.

Bangaram said:   1 decade ago
Kanna your explaination was good.

Akiii said:   1 decade ago
Kanna you are right.


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