Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 8 of 10.
Harish said:
1 decade ago
I don't think we should bother about 30 days' combined work. That piece of problem is, I think, meant to confuse us. Because he wishes to know B's individual capacity of doing what is left out by A's individual work.
Whatever A leaves behind, B finishes it.
Hence it is as simple as 16+44 = 60 days.
Whatever A leaves behind, B finishes it.
Hence it is as simple as 16+44 = 60 days.
Dhiraj said:
1 decade ago
Another way:
A + B = 60.
So A and B's together 1 day's work =1/60.
A's 1 day work = 1/16.
B's 1 day work = 1/44.
A works 16 days and leaves so int that A+B = 1/60, multiply A's work out of 60 days, Which gives number of work A has done.
Therefore 16/60=4/15 = A's work with B in 60 days.
Remaining work for 1 day = 1-4/15 = 11/15.
In those Remaining work has to Be done by B as he has to finish the work alone - 15/11*44 = 60 Days. This is Easy way.
A + B = 60.
So A and B's together 1 day's work =1/60.
A's 1 day work = 1/16.
B's 1 day work = 1/44.
A works 16 days and leaves so int that A+B = 1/60, multiply A's work out of 60 days, Which gives number of work A has done.
Therefore 16/60=4/15 = A's work with B in 60 days.
Remaining work for 1 day = 1-4/15 = 11/15.
In those Remaining work has to Be done by B as he has to finish the work alone - 15/11*44 = 60 Days. This is Easy way.
Abhilash said:
1 decade ago
How to solve alternative working days problem in time and work?
Avi said:
1 decade ago
For completion of one work it took A, B for 30 days.
So let A's one day work is x & B's one day work is y.
From above we can write 1 work=30x+30y.
But in second case a worked for 16 days & B worked for 44days.
Therefore,
16x+44y=1 work.
By solving we can get y=1/60 work.
So let A's one day work is x & B's one day work is y.
From above we can write 1 work=30x+30y.
But in second case a worked for 16 days & B worked for 44days.
Therefore,
16x+44y=1 work.
By solving we can get y=1/60 work.
Shraddha said:
1 decade ago
A's 16 days work + B's 44 days work = 1
(A+B) 16 days work + B's 28 days work = 1
but (A+B) 1 days work= 1/30
hence, (A+B) 16 days work = 8/15
therefore,
8/15 + B's 28 days work = 1
B's 28 days work = 1- 8/15
= 7/15
B's 1 days work = 1/60
(A+B) 16 days work + B's 28 days work = 1
but (A+B) 1 days work= 1/30
hence, (A+B) 16 days work = 8/15
therefore,
8/15 + B's 28 days work = 1
B's 28 days work = 1- 8/15
= 7/15
B's 1 days work = 1/60
Shraddha said:
1 decade ago
Multiply x+y=1/30 by 16 and that gives 16x+16y=8/15
subtract 16x + 16y = 8/15
-
16x + 44y =1
----------------
28y = 7/15
hence, y=1/60
substitute y= 1/60 in x+y=1/30 and we get, x=1/60
subtract 16x + 16y = 8/15
-
16x + 44y =1
----------------
28y = 7/15
hence, y=1/60
substitute y= 1/60 in x+y=1/30 and we get, x=1/60
Sushma said:
1 decade ago
Hi all
Can any one explain clearly above 1, that hw the answer would be x=1/60 & y=1/60............
I think we cant get it from abve eqns that 16x +44y=1
x+y=1/30
Can any one explain clearly above 1, that hw the answer would be x=1/60 & y=1/60............
I think we cant get it from abve eqns that 16x +44y=1
x+y=1/30
Ats said:
1 decade ago
Hi All,
Can somebody please explain me how solving the following equations.
1) x+y = 1/30.
2) 16x+44y = 1.
Result in x = 1/60 & why = 1/60 ?
Can somebody please explain me how solving the following equations.
1) x+y = 1/30.
2) 16x+44y = 1.
Result in x = 1/60 & why = 1/60 ?
Vino said:
1 decade ago
For eg:16x+44y=1:
A work is completed in 16days
For 16 days A's work is 16*x;
Remaining work=1-A's work...so
Remaining +A's work=1
Remaining work is done by 44 days=44*y
that's it.
A work is completed in 16days
For 16 days A's work is 16*x;
Remaining work=1-A's work...so
Remaining +A's work=1
Remaining work is done by 44 days=44*y
that's it.
Raj said:
1 decade ago
@vidya.
Given x and why worked for 30 days.
So, x and y's one days work is 1/30.
Given x and why worked for 30 days.
So, x and y's one days work is 1/30.
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