Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 6 of 10.
Ray said:
10 years ago
I have figure out the easiest way to understand the equation:
Let's say the speed of work done by each A and B in one day:
A+B = 1/30 (that's mean only (1/30)*100 = 3.33% whole work done).
In order to complete the whole task is 100%.
So, 16A+44B = (100/100) = 1.
This explained why the number 1 exist in the equation. The other part can be solved on your own.
Let's say the speed of work done by each A and B in one day:
A+B = 1/30 (that's mean only (1/30)*100 = 3.33% whole work done).
In order to complete the whole task is 100%.
So, 16A+44B = (100/100) = 1.
This explained why the number 1 exist in the equation. The other part can be solved on your own.
Pikot said:
9 years ago
Is there a formula?
SRI said:
9 years ago
1/30 - 1/16 = 7/240
2*1 / 44 = 1/22
7/240 - 1/22 = 43/2640
2*1 / 44 = 1/22
7/240 - 1/22 = 43/2640
Vinayan said:
9 years ago
Total work is equal to the LCM of 30, 16 & 44. ie 2640.
B finished the work in 2640/ 44 = 60 days.
B finished the work in 2640/ 44 = 60 days.
Mona said:
9 years ago
How we are getting 1 in the equation 16x+44y please Explain.
Jyoti Singh said:
9 years ago
Can anyone tell how to solve efficiency questions of time & work?
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Dhanesh ck said:
9 years ago
I will tell the simplest way. From this question, it's clear that A worked for 16 days and B worked for 44 days so 1/30 * 16 + 1/B * 28 = 1. So we get B = 60.
Dhakshina said:
9 years ago
Given X + Y =30.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
Bisu said:
9 years ago
Can somebody solve it in the shortcut?
Aakash said:
9 years ago
2 workers A + B together could finish a work in 8 days they work together for 6 days & A left the works the remaining works was completed by B alone in 6 days. How many days would each take to complete the individual?
How to solve this problem?
How to solve this problem?
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