Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 4 of 10.
Dhakshina said:
9 years ago
Given X + Y =30.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
Dhanesh ck said:
9 years ago
I will tell the simplest way. From this question, it's clear that A worked for 16 days and B worked for 44 days so 1/30 * 16 + 1/B * 28 = 1. So we get B = 60.
Jyoti Singh said:
9 years ago
Can anyone tell how to solve efficiency questions of time & work?
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Mona said:
9 years ago
How we are getting 1 in the equation 16x+44y please Explain.
Vinayan said:
9 years ago
Total work is equal to the LCM of 30, 16 & 44. ie 2640.
B finished the work in 2640/ 44 = 60 days.
B finished the work in 2640/ 44 = 60 days.
Pikot said:
9 years ago
Is there a formula?
Naseem Ahmad Saifi said:
10 years ago
There is no short cut for this @Ram is correct.
Puneet negi said:
8 years ago
A + b=30.
Let the efficiency of a and b is 1.
Then total work will be 30*2=60.
A did 16 work then remaining work is,
60-16=44 which will be completed by b in 44 days so B's actual efficiency is 1 so B will finish 60 work in 60 days.
Let the efficiency of a and b is 1.
Then total work will be 30*2=60.
A did 16 work then remaining work is,
60-16=44 which will be completed by b in 44 days so B's actual efficiency is 1 so B will finish 60 work in 60 days.
Shubham Singh said:
8 years ago
A+B completes work in 30 days, so,
=>unit of work done by both A and B in 1 day = 1/30,
Consider that total work done by both A and B = 30 units,
So,in 1 day = 1 unit work is done,
Since 1 day = 1 unit of work then A do 16 units of work,
Remaining work = 30-16 = 14 units,
This 14 units of work is done by B in remaining 28 days(44 days-16 days).
If we see read the question we get that "the total number of days required by B to complete the total 30 units" is asked.
So we do like this,
for 28 days = 14 units,
x days = 30 units,
we get 14*x = 28 * 30,
=>x = 28*30/14,
=>x=60 days.
=>unit of work done by both A and B in 1 day = 1/30,
Consider that total work done by both A and B = 30 units,
So,in 1 day = 1 unit work is done,
Since 1 day = 1 unit of work then A do 16 units of work,
Remaining work = 30-16 = 14 units,
This 14 units of work is done by B in remaining 28 days(44 days-16 days).
If we see read the question we get that "the total number of days required by B to complete the total 30 units" is asked.
So we do like this,
for 28 days = 14 units,
x days = 30 units,
we get 14*x = 28 * 30,
=>x = 28*30/14,
=>x=60 days.
Sagar parida said:
8 years ago
Please, anyone help me out from this question--.
A and B can do a work together in 10 days, B and C can do the same work in 18 days, if A starts the work and after working 5 days B do the work for 15 days and remaining work in done by C than find in how many days will C complete the work alone?
A and B can do a work together in 10 days, B and C can do the same work in 18 days, if A starts the work and after working 5 days B do the work for 15 days and remaining work in done by C than find in how many days will C complete the work alone?
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