Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 16)
16.
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
6 days
10 days
15 days
20 days
Answer: Option
Explanation:

Work done by X in 4 days = 1 x 4 = 1 .
20 5

Remaining work = 1 - 1 = 4 .
5 5

(X + Y)'s 1 day's work = 1 + 1 = 8 = 2 .
20 12 60 15

Now, 2 work is done by X and Y in 1 day.
15

So, 4 work will be done by X and Y in 15 x 4 = 6 days.
5 2 5

Hence, total time taken = (6 + 4) days = 10 days.

Discussion:
68 comments Page 4 of 7.

Makvana Disha said:   9 years ago
@Sachin,

2/15 = 1 day work.
Then for remaining work 4/5 = ?
i.e. (4/5) * (15/2) = 6 days.

Total days are, 6 + 4 = 10 days.

Nishesh kumar singh said:   4 years ago
@All.

4/5 is the remaining work which is divided by 2/15 which is 1-day work by x and y to find the no. Of days i.e.4/5/2/15.
(1)

Sudharsan said:   6 years ago
Why we are adding +4 to the sum the 6 is the work completed until the last. X+4 is just a time taken, why anyone explain?
(3)

Aakash said:   1 decade ago
x+4/20+x/12 = 1.
3(x+4)+5(x)/60 = 1.
3x+12+5x = 60.
8x+12 = 60.
8x = 60-12.
8x = 48.
x = 6.

i.e., x+4 = 6+4.

10 days.

Ajay said:   8 years ago
x+4/20+x/12 = 1.
3(x+4)+5(x)/60 = 1.
3x+12+5x = 60.
8x+12 = 60.
8x = 60-12.
8x = 48.
x = 6.
i.e., x+4 = 6+4.

10 days.

Shro said:   1 decade ago
6+4 =10
Is here 4 takes from the question? " X started the work alone and then after 4 days"

Anusha said:   1 decade ago
a = b+b (0.3).

(1/23) = 1.3 b.

b = (10/{23*13}).

b = (10/299).

a+b = 1/13.

So 13 days.

Sachin said:   9 years ago
Please help me to understand this, why we took 15/2 instead of 2/15?

Thank in advance.

Nik said:   9 years ago
But here it asked like "how long did they work", why should we consider A's work here?

Nikhil said:   2 decades ago
2/15 work done by x and y in one day.

Then how you are taking reciprocal 15/2*4/5.


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